If you have a discontinuity and you can cancel factors in the numerator and the denominator, then it is removable. If you can't cancel those factors to get rid of the discontinuity it is nonremovable. Here is an example that shows both kinds. f(x) = (x - 2)(x + 3) /[(x - 2) (x - 4) There is a discontinuity at x=2 but we can cancel out(x-2) from the top and bottom. That makes it removable. However, at x=4 there also a discontinuity and there is no way to remove that one.
"Removable discontinuity" means the function is not defined at that point (it has a "hole"), but by changing the function definition at that single point, defining it to be certain value, it becomes continuous. "Irremovable discontinuity" means the function makes a sudden jump at that point. There are infinitely many functions like that; for example, you can set the function to be: f(x) is undefined at x = -2 f(x) = 0 for x < 2 (except for x = -2) f(x) = 1 for x > 2
The graph of an exponential function f(x) = bx approaches, but does not cross the x-axis. The x-axis is a horizontal asymptote.
An asymptote is the tendency of a function to approach infinity as one of its variable takes certain values. For example, the function y = ex has a horizontal asymptote at y = 0 because when x takes extremely big, negative values, y approaches a fixed value : 0. Asymptotes are related to limits.
The asymptote is a line where the function is not valid - i.e the function does not cross this line, in fact it does not even reach this line, so you cannot check the value of the function on it's asymptote.However, to get an idea of the function you should look at it's behavior as it approaches each side of the asymptote.
2x-2/x^2+3x-4
A vertical asymptote can be, but need not be a discontinuity. In simple terms, the distinction depends whether the domain extends on only one side of the (no discontinuity) or both sides (infinite discontinuity). For example, there is no discontinuity in f(x) = 1/x for x > 0 On the other hand, f(x) = 1/x for x ≠0 has an infinite discontinuity at x = 0.
If you have a discontinuity and you can cancel factors in the numerator and the denominator, then it is removable. If you can't cancel those factors to get rid of the discontinuity it is nonremovable. Here is an example that shows both kinds. f(x) = (x - 2)(x + 3) /[(x - 2) (x - 4) There is a discontinuity at x=2 but we can cancel out(x-2) from the top and bottom. That makes it removable. However, at x=4 there also a discontinuity and there is no way to remove that one.
Non-removable discontinuity, nonagon, and nonexistent answer are just a few math words that start with non.
In a parabolic curve it would be called an asymptote, where only one integer is exluded. If multiple integers are excluded, or you are dealing with piece-wise functions it is called a jump discontinuity.
"Removable discontinuity" means the function is not defined at that point (it has a "hole"), but by changing the function definition at that single point, defining it to be certain value, it becomes continuous. "Irremovable discontinuity" means the function makes a sudden jump at that point. There are infinitely many functions like that; for example, you can set the function to be: f(x) is undefined at x = -2 f(x) = 0 for x < 2 (except for x = -2) f(x) = 1 for x > 2
A circle does not have an asymptote.
Asymptote Architecture was created in 1989.
No. If it cuts a graph it is not an asymptote.
No if the denominators cancel each other out there is no asymptote
An asymptote is a line or curve that approaches a given curve arbitrarily closely.
It has no asymptote. 3x is a straight line and therefore is a tangent to itself.