"Removable discontinuity" means the function is not defined at that point (it has a "hole"), but by changing the function definition at that single point, defining it to be certain value, it becomes continuous. "Irremovable discontinuity" means the function makes a sudden jump at that point. There are infinitely many functions like that; for example, you can set the function to be:
f(x) is undefined at x = -2
f(x) = 0 for x < 2 (except for x = -2)
f(x) = 1 for x > 2
That's true. If a function is continuous, it's (Riemman) integrable, but the converse is not true.
Υou show that it is continuous in every element of it's domain.
continuous
No. Not all functions are continuous. For example, the function f(x) = 1/x is undefined at x = 0.
The way I understand it, a continuos function is said not to be "uniformly continuous" if for a given small difference in "x", the corresponding difference in the function value can be arbitrarily large. For more information, check the article "Uniform continuity" in the Wikipedia, especially the examples.
No. It has a discontinuity at every integer value.
A discontinuity of the first kind occurs when a function's limit does not exist at a specific point, while a discontinuity of the second kind happens when the function's value at a particular point is undefined or infinite. Discontinuities of the first kind can be classified as removable, jump, or infinite discontinuities, based on the behavior of the limit.
2x-2/x^2+3x-4
A piece-wise continuous function is one which has a domain that is broken up inot sub-domains. Over each sub-domain the function is continuous but at the end of the domain one of the following possibilities can occur:the domain itself is discontinuous (disjoint domains),the value of the function is not defined at the start or end-point of the domain ((a hole),the value of the function at the end point of a sub-domain is different to its value at the start of the next sub-domain (a step-discontinuity).A piece-wise continuous function is one which has a domain that is broken up inot sub-domains. Over each sub-domain the function is continuous but at the end of the domain one of the following possibilities can occur:the domain itself is discontinuous (disjoint domains),the value of the function is not defined at the start or end-point of the domain ((a hole),the value of the function at the end point of a sub-domain is different to its value at the start of the next sub-domain (a step-discontinuity).A piece-wise continuous function is one which has a domain that is broken up inot sub-domains. Over each sub-domain the function is continuous but at the end of the domain one of the following possibilities can occur:the domain itself is discontinuous (disjoint domains),the value of the function is not defined at the start or end-point of the domain ((a hole),the value of the function at the end point of a sub-domain is different to its value at the start of the next sub-domain (a step-discontinuity).A piece-wise continuous function is one which has a domain that is broken up inot sub-domains. Over each sub-domain the function is continuous but at the end of the domain one of the following possibilities can occur:the domain itself is discontinuous (disjoint domains),the value of the function is not defined at the start or end-point of the domain ((a hole),the value of the function at the end point of a sub-domain is different to its value at the start of the next sub-domain (a step-discontinuity).
Yes. The cosine function is continuous. The sine function is also continuous. The tangent function, however, is not continuous.
yes it is a continuous function.
There are no points of discontinuity for exponential functions since the domain of the general exponential function consists of all real values!
Yes, a polynomial function is always continuous
That's true. If a function is continuous, it's (Riemman) integrable, but the converse is not true.
Weistrass function is continuous everywhere but not differentiable everywhere
Yes, that happens with any continuous function. The limit is equal to the function value in this case.Yes, that happens with any continuous function. The limit is equal to the function value in this case.Yes, that happens with any continuous function. The limit is equal to the function value in this case.Yes, that happens with any continuous function. The limit is equal to the function value in this case.
An infinite sum of continuous functions does not have to be continuous. For example, you should be able to construct a Fourier series that converges to a discontinuous function.