graph y = k^x where k is >1.
it will have a y-intercept of (0,1) because anything to the zero power = 1. It then increases rapidly in the 1st quadrant. The graph also passes thru (1,k) in te first quad. In the second quadrant, as the x value becomes more negative, the graph approaches the x -axis, this is called an asymptote, because the y values become smaller and smaller. All x values are negative in the 2nd quad thus creating reciprocals (defn of neg exponent). The graph passes thru (-1, 1/k) in 2nd quad.
EX y = 2^x passes thru (0,1) y-intercept
1st quad thru (1,2) because k =2 and then increases rapidly
2nd quad thru (-1, 1/2) remember to approach the x-axis to the left,
Chat with our AI personalities
The equation 2x - 3y = 6 is a linear equation and a linear equation is always has a straight line as a graph
they have same slop.then two linear equations have infinite solutions
It would look like a straight vertical line, i.e. parallel to the y-axis, passing through the point on the x-axis where x=3.
I suggest you use an online graphing calculator to do this. For example, you might try Wolfram Alpha.
'x^(2)' looks like a bowl on a graph. '-x^(2)' looks like an upturned bowl, or an umbrella.