(3x + 3y)(x + y) = 3(x + y)2
(3x + 1)(x + 5)
(x + 5)(3x + 1)
(3x - 2)(x + 8)
(x - 1)(3x + 5)
It is: 3x*(x+7)
(3x + 3y)(x + y) = 3(x + y)2
(3x + 1)(x + 5)
(x + 5)(3x + 1)
(x + 2)(x + 1)
If that's -18y2, the answer is (3x - 2y)(x + 9y)
(3x - 2)(x + 8)
(x - 1)(3x + 5)
-1
3(x + 4)(x + 1)
(x^2 - 3x + 5)(x^2 + 3x + 5)
(x - 6)(x + 9)