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What are the 4 diget combanations for the numbers 0-9?
Let the digit be x x x x The first space can be filled in 9 ways as 0 is excluded. The second space can be filled in 9 ways as 0 is included. The third in 8 ways and the fourth in 7 ways. Total number of permutations (assuming all of the digits are different) is 9 x 9 x 8 x 7 = 4,536. If you assume the digits can repeat, the number of permutations become 9 x 10 x 10 x 10 = 9,000.
What is the factor of 3x2 2x 2 equals 0?
3x2 + 2x + 2 = 0 Can not be factored. You can however solve it for x: 3x2 + 2x = -2 x2 + 2x/3 = -2/3 x2 + 2x/3 + 1/9 = -2/3 + 1/9 (x + 1/9)2 = -5/9 x + 1/9 = ±√(-5/9) x = -1/9 ± i√(5/9) x = -1/9 ± i√5 / 3 x = -1/9 ± 3i√5 / 9 x = (-1 ± 3i√5) / 9
What is X 2-6x-2 0 completing the square?
x^2 - 6x - 2 = 0 x^2 - 6x = 2 x^2 - 6x + 9 = 2 + 9 = 11 (x - 3)^2 = 11 x - 3 = +/- sqrt(11) x = 3 +/- sqrt(11)
How do you solve this log x base 3 plus log x3 base 9 equal 0?
log3(x) + log9(x^3)=0 for any t >0 logt(x) = ln(x)/ln(t) so log9(x) = ln(x) / ln (9) = ln (x) / ( 2 * ln 3) = log3(x) /2 or log3(x) = 2 log9(x) log9(x^n) = n * log9(x) So log3(x) + log9(x^3) = log3(x) + 6 log3(x) = 7 log3(x) 7 log3(x) = 0 => log3(x) = 0 => x = 1
What equation has a solution of 9?
Of course, x-1=8 is a solution. Any equation which results with the variable value as 9 is ur answer. For eg: x = 9 / x-9 = 0 1 - x = -8 / x-1 = 8 x-2 = 7 / 2-x = -7 Any, any such equation will be your answer(correct answer). Enjoy
