0
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals".
Add your answer:
Earn +20 pts
How do you prove tan x plus tan x sec 2x equals tan 2x?
tan x + (tan x)(sec 2x) = tan 2x work dependently on the left sidetan x + (tan x)(sec 2x); factor out tan x= tan x(1 + sec 2x); sec 2x = 1/cos 2x= tan x(1 + 1/cos 2x); LCD = cos 2x= tan x[cos 2x + 1)/cos 2x]; tan x = sin x/cos x and cos 2x = 1 - 2 sin2 x= (sin x/cos x)[(1 - 2sin2 x + 1)/cos 2x]= (sin x/cos x)[2(1 - sin2 x)/cos 2x]; 1 - sin2 x = cos2 x= (sin x/cos x)[2cos2 x)/cos 2x]; simplify cos x= (2sin x cos x)/cos 2x; 2 sinx cos x = sin 2x= sin 2x/cos 2x= tan 2x
Factor 2x squared plus 2x plus xy plus y?
4
Find the derivative of y x2 sin x 2xcos x - 2sin x?
y = (x^2)(sin x)(2x)(cos x) - 2sin xy' = [[(x^2)(sin x)][(2x)(cos x)]]' - (2sin x)'y' = [[(x^2)(sin x)]'[(2x)(cos x)] + [(2x)(cos x)]'[(x^2)(sin x)]]- (2sin x)'y' = [[(x^2)'(sin x) + (sin x)'(x^2)][(2x)(cos x)] + [(2x)'(cos x) + (cos x)'(2x)][(x^2)(sin x)] ] - 2(cos x)y' = [[(2x)(sin x )+ (cos x)(x^2)][(2x)(cos x)] + [2cos x - (sin x)(2x)][(x^2)(sin x)]] - 2(cos x)y' = (4x^2)(sin x cos x) + (2x^3)(cos x)^2 + (2x^2)(sin x cos x) - (2x^3)(sin x)^2 - 2cos xy' = (6x^2)(sin x cos x) + (2x^3)(cos x)^2 - (2x^3)(sin x)^2 - 2cos x (if you want, you can stop here, or you can continue)y' = (3x^2)(2sin x cos x) + (2x^3)[(cos x)^2 - (sin x)^2] - 2cos xy' = (3x^2)(sin 2x) + (2x^3)(cos 2x) - 2 cos xy' = (2x^3)(cos 2x) + (3x^2)(sin 2x) - 2 cos x
2x-3 equals x plus 5?
2x-3 = x+5 2x-x = 8 x = 8
2x - 6 4?
2x-6=4 6+4=2x 10=2x 10/2=x 5=x x=5
2x 39 what does x equal?
If I understand the question correctly: 2x=39 then x=39/2 or x=19.5
What is the answer for this equation x squared plus 2x-38 equals 0?
x2 + 2x - 38 = 0 ∴ x2 + 2x + 1 = 39 ∴ (x + 1)2 = 39 ∴ x + 1 = ±√39 ∴ x = -1 ±√39
How do you solve 2x 39 X?
2x+3=9 x
What is 2x plus 39 x?
This is 41x
If the base of an isosceles triangle is 11 and the perimeter is 39 what is the length of a leg-?
Let the length of a leg be x. There are three sides: the base which is 11, and the legs, which are both x: 11 + x + x = 39 2x+11 = 39 2x = 39-11 2x = 28 x = 28/2 x = 14 The length of one leg is 14 units.
2x plus 24 equals 9x-39?
2x + 24 = 9x - 39= 2x + 63 = 9x= 63 = 7x= x = 9
What is the gcd of 39 and 26?
There can be no greatest common denominator. Suppose x is the greatest common denominator. That requires that 39 divides x, 26 divides x and x is the greatest such number. But 39 will divide 2x and 26 will divide 2x and 2x is greater than x. So x could not have been a GCD.
What is 2x plus 39.X?
This is 41x
Solve 8x plus 39 equals 2x-15?
8x+39 = 2x-15 6x = -54 x = -9
What is 2x plus 6 plus 9x equals 39?
2x + 6 + 9x = 39 11x + 6 = 39 11x = 39 - 6 11x = 33 x = 3
What is x if 2x equals 39?
Your problem is 2x = 39. To figure out what x is, you first have to get rid of the 2 that is attached to the x. To get get rid of it, you have to do the opposite. In this case, that means you have to divide both sides by two. When I put parathesis around it, that means I'm dividing the whole thing by two. (2x = 39) / 2 = 19.5 So that means x=19.5
Multiply this number by 4 and subtract 39 to get twice the number plus 3?
4x-39 = 2x+3, 4x-2x = 42 x=21
