C and D
c = 4, c squared = 16, 3c squared = 48, 48 + 9 = 57.
C. (2, 5) d. (-4, -13)
k=log4 91.8 4^k=91.8 -- b/c of log rules-- log 4^k=log 91.8 -- b/c of log rules-- k*log 4=log91.8 --> divide by log 4 k=log 91.8/log 4 k= 3.260
9x2 - 12x + 4 = 0 is of the form ax2 + bx + c = 0 where the discriminant, D, can be found by D = b2 - 4ac First, you find the values of a, b and c: a = 9 b = -12 c = 4 Now you can find D: D = (-12)2 - (4)(9) = 144 - 36 = 108 D = 108
4
Just substitute the "c" with 4 and the "a" with negative 5, as c=4 and a=-5. So the equation is 4-(-5) which is simply 4+5. And the rest you should be able to do from there.
t = 4/5
C equals negative 1
And what is the question?
144 Formula: c= (a2)+(ab)
Its evaluation is: (4*5)+(7*3) = 41
C plus is between 3 and 3.2. C = 75% 0% < Plus < 5% 75%+0% < C Plus < 75%+5% 75 < C Plus < 80% 75%*4 < C Plus < 80% * 4 (3/4)*4 < C Plus < (4/5) * 4 3 < C Plus < 16/5 3 < C Plus < 3.2
ac is 7 if b is 3 and a is 2 a nd c is 5
-4 + c = -9 -4 + 4 + c = -9 +4 c = -9 + 4 c = -5
(7 x 7) - (5 x 3)
It depends on the value of c. If c = 0 then 0-0+5 = 5 If c = 1 then 1-2+5 = 4 If c = 2 then 4-4+5 = 5 and so on.