ac is 7 if b is 3 and a is 2 a nd c is 5
5
Yes, you can find the measure of side BC using the Pythagorean theorem. Since triangle ABC is a right triangle and if AC is one leg (5) and AB is the hypotenuse (10), you can calculate BC as follows: ( BC^2 = AB^2 - AC^2 ), which gives ( BC^2 = 10^2 - 5^2 = 100 - 25 = 75 ). Therefore, ( BC = \sqrt{75} ) or approximately 8.66.
To determine the length of BC, we need more information about the relationship between points A, B, C, D, E, and F, such as the configuration of these points (e.g., are they on a straight line, a triangle, etc.). Without additional context or a diagram, we cannot calculate the length of BC based solely on the provided lengths of AB, AC, DE, DF, and EF.
Use the cosine rule: a2 = b2+c2-2bc*cos A BC2 = AB2+AC2-2*AB*AC*cos A BC2 = 32+52-2*3*5*cos 57 BC2 = 17.66082895 BC = 4.20247887 cm in length
That depends on the value of CD and the perimeter of the quadrilateral out lined in the question
5
AC=5 AB=8 A=1 B=8 C=5 BC=40
Yes, you can find the measure of side BC using the Pythagorean theorem. Since triangle ABC is a right triangle and if AC is one leg (5) and AB is the hypotenuse (10), you can calculate BC as follows: ( BC^2 = AB^2 - AC^2 ), which gives ( BC^2 = 10^2 - 5^2 = 100 - 25 = 75 ). Therefore, ( BC = \sqrt{75} ) or approximately 8.66.
If AC equals 6 and BD equals 4, then AB equals 5.
9_or_yes">9 or yesA+ = 12
To determine the length of BC, we need more information about the relationship between points A, B, C, D, E, and F, such as the configuration of these points (e.g., are they on a straight line, a triangle, etc.). Without additional context or a diagram, we cannot calculate the length of BC based solely on the provided lengths of AB, AC, DE, DF, and EF.
Use the cosine rule: a2 = b2+c2-2bc*cos A BC2 = AB2+AC2-2*AB*AC*cos A BC2 = 32+52-2*3*5*cos 57 BC2 = 17.66082895 BC = 4.20247887 cm in length
If CB is the hypotenuse, then AB measures, √ (62 - 52) = √ 11 = 3.3166 (4dp) If AB is the hypotenuse then it measures, √ (62 + 52) = √ 61 = 7.8102 (4dp)
If these are sides of a triangle then AC can have any value in the interval (3, 13).
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Since AB and AC are tangent to the circle O, it seems that they both are drawn from the same outside point A. As tangents to a circle from an outside point are congruent, AB ≅ BC. Also, a tangent is perpendicular to radius drawn to point of contact. So that OB and OC are congruent radii. Therefore, the perimeter of the quadrilateral ABOC equals to P = 2(12 cm) + 2(5 cm) = 34 cm.
The length is sqrt(61) units.