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If AC equals 15 centimeters and BC equals 12 centimeters which does AB equal?
5
What is the length of BC in the triangle ABC when AB equals 3 cm AC equals 5 cm and angle A is 57 degrees?
Use the cosine rule: a2 = b2+c2-2bc*cos A BC2 = AB2+AC2-2*AB*AC*cos A BC2 = 32+52-2*3*5*cos 57 BC2 = 17.66082895 BC = 4.20247887 cm in length
If AD equals 3x plus 5 AB equals 7x-3 and BC equals 8x-10 what is the value of x?
That depends on the value of CD and the perimeter of the quadrilateral out lined in the question
A and b are events with complements ac and bc and if p of a is point 3 and p of b is point 5 find p of ac and bc?
The probability of ac and bc is 1/5.
If a equals 5 and b equals 8 will be ab?
40?
If AC equals 15 centimeters and BC equals 12 centimeters which does AB equal?
5
What is BC if AC is 5 and AB is 8?
AC=5 AB=8 A=1 B=8 C=5 BC=40
If triangle AC equals 6 and BD equals 4 find AB?
If AC equals 6 and BD equals 4, then AB equals 5.
Triangle abc is a right triangle. If side AC equals 5 and side AB equals 10 what is the measure of side BC?
9_or_yes">9 or yesA+ = 12
What is the length of BC in the triangle ABC when AB equals 3 cm AC equals 5 cm and angle A is 57 degrees?
Use the cosine rule: a2 = b2+c2-2bc*cos A BC2 = AB2+AC2-2*AB*AC*cos A BC2 = 32+52-2*3*5*cos 57 BC2 = 17.66082895 BC = 4.20247887 cm in length
If AB 5 and BC 8 then AC?
If these are sides of a triangle then AC can have any value in the interval (3, 13).
Triangle abc is a right triangle if side ac equals 5 and side bc equals 6 what is the measure of side ab?
If CB is the hypotenuse, then AB measures, √ (62 - 52) = √ 11 = 3.3166 (4dp) If AB is the hypotenuse then it measures, √ (62 + 52) = √ 61 = 7.8102 (4dp)
In cirlce o radius op intersects chord ac in point b so that ab equals 5 units and bs equals 5 units this means that op is perpendicular to ac?
truee buddyy (;
In the given right triangle find the length of the hypotenuse AB if BC 6 and AC 5.?
The length is sqrt(61) units.
Ab and ac are tangents to a circle with centre o and radius 5cmif ac equals 12cmfind the perimeter of quadrilateral aboc?
Since AB and AC are tangent to the circle O, it seems that they both are drawn from the same outside point A. As tangents to a circle from an outside point are congruent, AB ≅ BC. Also, a tangent is perpendicular to radius drawn to point of contact. So that OB and OC are congruent radii. Therefore, the perimeter of the quadrilateral ABOC equals to P = 2(12 cm) + 2(5 cm) = 34 cm.
If AD equals 3x plus 5 AB equals 7x-3 and BC equals 8x-10 what is the value of x?
That depends on the value of CD and the perimeter of the quadrilateral out lined in the question
A and b are events with complements ac and bc and if p of a is point 3 and p of b is point 5 find p of ac and bc?
The probability of ac and bc is 1/5.
