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Solve the following system of equations using substitutions 2x plus 3y equals -1 and 5x-2y equals -12?
First get y in terms of x: 5x-2y=-12 ----- -2y=-12-5x ------ y=6+(5/2)x Sub into other equation: 2x+3y=-1 ---- 2x+3(6+(5/2)x)=-1 Solving for x gets: x= -2 Sub into other equation: 5x-2y= -12 --- 5(-2)-2y= -12 --- y=1 So x= -2, and y= 1
What is the graph of the equation -5x plus 2y equals 2?
A straight line through the points (0, 1) and (-0.4, 0).
What are the solutions to the simultaneous equations of 2x -3y equals 4 and 5x plus 2y equals 1?
Equations: 2x-3y = 4 and 5x+2y = 1 Multiply all terms in 1st equation by 5 and all terms in 2nd equation by 2:- So: 10x-15y = 20 and 10x+4y = 2 Subtract the 2nd equation from the 1st equation: -19y = 18 => y = -18/19 By substitution the solutions are: x = 11/19 and y = -18/19
Is point 1 4 on the line represented by the equation x plus 2y equals 5?
The equation "x plus 2y equals 5" is: x + 2y = 5 2y = 5 - x y = 5/2 - 1/2x y = -1/2x + 5/2
Is x equals 0 no solution?
Zero is an acceptable value for a variable. As a general rule, if you solve an equation and get x equals zero, that's just what it is: zero. There is one solution. Example: 10x +1 = 5x +1 5x = 1 - 1 5x = 0 x = 0 There is one solution, zero. If you solve for x and get two solutions, such as 2 and 0, there are two answers. Later on, if you've studied domain and range (the numbers you can use for x so that the equation is still defined, (i.e. not 1/0, or the square root of negative 1), you may find that x = 0 does not always work. You need to check first, to see if zero is in the domain, before you say it's an answer.
What is a solution to the equation 5x 2y-1?
Without an equality sign it cannot be classed as an equation therefore it follows that there is no solution.
What is equation of 3x plus 2y equals 8 and 5x plus 2y equals 12?
Both of them are equations!The solution is (x, y) = (2, 1).
What is the solution of 2y-x equals 3 and y equals -5x plus 7?
2y - x = 3 y = -5x + 7 Rewrite the second y + 5x = 7 Mutiply it by 2 2y + 10x = 14 Now subtract the first equation from this: 2y + 10x = 14 2y - x = 3 11x = 11 Divide both sides by 11: x = 1 Substitute for x in the first equation: 2y - 1 = 3 Add 1 to both sides: 2y = 4 Divide both sides by 2: y = 2 Answer: (x, y) = (1, 2)
5x plus 3y equals 17 5x - 2y equals -3?
Multiply the bottom equation by -1
What is the solution to 2y equals 5x - 1 x equals y plus 2?
If those are two different equations, such that 2y=5x-1 and x=y+2, then you subsitute y+2 in for x in the first equation, and when you solve the whole thing, you get that x=-1 and y=-3, or the point (-1,-3)
Solve the following system of equations using substitutions 2x plus 3y equals -1 and 5x-2y equals -12?
First get y in terms of x: 5x-2y=-12 ----- -2y=-12-5x ------ y=6+(5/2)x Sub into other equation: 2x+3y=-1 ---- 2x+3(6+(5/2)x)=-1 Solving for x gets: x= -2 Sub into other equation: 5x-2y= -12 --- 5(-2)-2y= -12 --- y=1 So x= -2, and y= 1
Isha sharma writes three liner equations in two variables as under 3x plus 2y equals 5 5x-7y equals -2 6x plus 4y equals 10which pairs has no solution?
There is no such pair. The solution to equation 1 and equation 2 is x = 1, y = 1. The solution to equation 2 and equation 3 is x = 1, y = 1. And the solution to equation 1 and equation 3 is any point on the line 3x + 2y = 5 - an infinite number of solutions. The fact that the determinant for equations 1 and 3 is zero (or that they are not independent) does not mean that there is no solution. It means that there is no UNIQUE solution. In this particular case, the two equations are equivalent and so have an infinite number of solutions.
Solve this equation using substitution 5x plus y equals 1 and 3x plus 2y plus 2?
It is not possible to do so because the question contains one equation (5x + y = 1) and one expression (3x + 2y + 2). An expression cannot be solved.
5x plus y equals 5 3x plus 2y equals 3?
Double first equation: 10x + 2y = 10Subtract second equation: 7x = 7x = 1, y = 0
3x plus 2y equals 20 and 5x-2y equals 1?
3x+2y=20 5x-2y=1 (3x+2y) + (5x-2y)= 20+1 3x+5x= 21....... 8x=21.........x=2 5/8 Subsitute x=3(2 5/8)+ 2y=20........... 7 7/8 +2y=20.........2y= 20- 7 7/8....... y=6 1/16
What would the solution for the equation 4 3 x plus 2 equals 5x?
In the equation 43X +2=5X, X=-1/19.
What Is 2y plus 4a equals?
x-2y+bz=3 ax+2z=2 5x+2y=1 find values of a and b for which the system of linear equation has infinitely many solutions
