∫ d/dx f(x) dx = f(x) + C C is the constant of integration.
If it is with respect to t: 1 If it is with respect to some other variable (x for example): (dt)/(dx), which is literally read "the derivative of t with respect to x"
If x is a function of time, t, then the second derivative of x, with respect to t, is the acceleration in the x direction.
∫ 1/cos(x) dx = ln(sec(x) + tan(x)) + C C is the constant of integration.
for solving this ..the first thing to do is substitute tanx=t^2 then x=tan inverse t^2 then solve the integral..
Assuming integration is with respect to a variable, x, the answer is 34x + c where c is the constant of integration.
∫ d/dx f(x) dx = f(x) + C C is the constant of integration.
If it is with respect to t: 1 If it is with respect to some other variable (x for example): (dt)/(dx), which is literally read "the derivative of t with respect to x"
∫ sin(x) dx = -cos(x) + CC is the constant of integration.
∫ cos(x) dx = sin(x) + CC is the constant of integration.
∫ cot(x) dx = ln(sin(x)) + CC is the constant of integration.
∫ f'(x)/f(x) dx = ln(f(x)) + C C is the constant of integration.
∫ ex dx = ex + CC is the constant of integration.
∫ (1/x) dx = ln(x) + C C is the constant of integration.
∫ sinh(x) dx = cosh(x) + C C is the constant of integration.
∫ tan(x) dx = -ln(cos(x)) + C C is the constant of integration.
∫ cosh(x) dx = sinh(x) + C C is the constant of integration.