This equation is unsolvable as x2 cannot be a negative number as would be suggested by this equation. Any number, even a negative, multiplied by itself will always give a positive number but this equation leaves you with x2 = -48
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x2+11x+11 = 7x+9 x2+11x-7x+11-9 = 0 x2+4x+2 = 0 The above quadratic equation can be solved by using the quadratic equation formula and it will have two solutions.
Draw a circle with its center at the origin and a radius of 3.
x2 + 6x - 2 = 0 x2 + 6x + 9 = 13 (x + 3)2 = 13 x + 3 = ± √13 x = -3 ± √13
c = 4, c squared = 16, 3c squared = 48, 48 + 9 = 57.
The discriminant formula. b2 - 4ac 32 - 4(1)(8) 9 - 32 = - 23 ===========This shows no real roots to this function.