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What is the antiderivative of 8 pi?
The antiderivative of a constant, such as (8\pi), is found by multiplying the constant by the variable of integration and adding a constant of integration (C). Thus, the antiderivative of (8\pi) with respect to (x) is (8\pi x + C), where (C) represents any constant.
What is the antiderivative of x raised to the pi power?
x(pi+1)/(pi+1)
What is the antiderivative of -10x4?
I assume you mean -10x^4? In that case, antiderivative would be to add one to the exponent, then divide by the exponent. So -10x^5, then divide by 5. So the antiderivative is -2x^5.
What is the antiderivative of x to the 1?
By antiderivative do you mean integral? If yes, integral x^1 dx= (x^2)/2
What is the antiderivative of x to the negative 6 5ths?
(that weird integral or antiderivative sign) x^(-6/5) dx =-5*x^(-1/5)
What is the antiderivative of 8 pi?
The antiderivative of a constant, such as (8\pi), is found by multiplying the constant by the variable of integration and adding a constant of integration (C). Thus, the antiderivative of (8\pi) with respect to (x) is (8\pi x + C), where (C) represents any constant.
What is the antiderivative of x raised to the pi power?
x(pi+1)/(pi+1)
What is the antiderivative of 2x?
The antiderivative of 2x is x2.
What is the antiderivative of zero?
The antiderivative of a function which is equal to 0 everywhere is a function equal to 0 everywhere.
Which is the antiderivative of sinxcosx?
Using u-substitution (where u = sinx), you'll find the antiderivative to be 0.5*sin2x + C.
What is the antiderivative of -10x4?
I assume you mean -10x^4? In that case, antiderivative would be to add one to the exponent, then divide by the exponent. So -10x^5, then divide by 5. So the antiderivative is -2x^5.
What is the antiderivative of x to the -1?
Antiderivative of x/-1 = -1(x^2)/2 + C = (-1/2)(x^2) + C Wolfram says antiderivative of x^-1 is log(x) + C
What is the antiderivative of x to the 1?
By antiderivative do you mean integral? If yes, integral x^1 dx= (x^2)/2
How do you take the integral from negative infinity to 4 of 1 over1 plus x2?
Recall that the antiderivative of 1/(1+x2) is arctan(x). arctan(negative infinity) = -pi/2. arctan(4) = approximately 1.325818. The answer then is arctan(4) - (pi/2) = approximately -0.244979
What is the fundamental theory of calculus?
The fundamental theorum of calculus states that a definite integral from a to b is equivalent to the antiderivative's expression of b minus the antiderivative expression of a.
What is the antiderivative of x to the negative 6 5ths?
(that weird integral or antiderivative sign) x^(-6/5) dx =-5*x^(-1/5)
What is the antiderivative of exp -x?
It is -exp (-x) + C.
