x(pi+1)/(pi+1)
35x2
I assume you mean -10x^4? In that case, antiderivative would be to add one to the exponent, then divide by the exponent. So -10x^5, then divide by 5. So the antiderivative is -2x^5.
By antiderivative do you mean integral? If yes, integral x^1 dx= (x^2)/2
(that weird integral or antiderivative sign) x^(-6/5) dx =-5*x^(-1/5)
x(pi+1)/(pi+1)
The antiderivative of 2x is x2.
The antiderivative of a function which is equal to 0 everywhere is a function equal to 0 everywhere.
35x2
Using u-substitution (where u = sinx), you'll find the antiderivative to be 0.5*sin2x + C.
I assume you mean -10x^4? In that case, antiderivative would be to add one to the exponent, then divide by the exponent. So -10x^5, then divide by 5. So the antiderivative is -2x^5.
Antiderivative of x/-1 = -1(x^2)/2 + C = (-1/2)(x^2) + C Wolfram says antiderivative of x^-1 is log(x) + C
Recall that the antiderivative of 1/(1+x2) is arctan(x). arctan(negative infinity) = -pi/2. arctan(4) = approximately 1.325818. The answer then is arctan(4) - (pi/2) = approximately -0.244979
By antiderivative do you mean integral? If yes, integral x^1 dx= (x^2)/2
The fundamental theorum of calculus states that a definite integral from a to b is equivalent to the antiderivative's expression of b minus the antiderivative expression of a.
(that weird integral or antiderivative sign) x^(-6/5) dx =-5*x^(-1/5)
-e-x + C.