4y = 2y + 40 4y - 2y = 2y -2y +40 2y = 40 y = 20 check 4(20) = 2(20) +40 80 = 80
-2y = 10 2y = -10 y = -5
3x = 2y + 3 3x -3 = 2y +3 -3 3x - 3 = 2y (3x -3)/2 = 2y / 2 y = 1/2 x (3x - 3) 3x = 2y +3 3x - 3x = -3x +2y +3 0 = -3x +2y +3 -1 x (0) = -1 x (-3x +2y +3) 0 = 3x - 2y -3
A dot A = A2 do a derivative of both sides derivative (A) dot A + A dot derivative(A) =0 2(derivative (A) dot A)=0 (derivative (A) dot A)=0 A * derivative (A) * cos (theta) =0 => theta =90 A and derivative (A) are perpendicular
The derivative of e7x is e7 or 7e.The derivative of e7x is 7e7xThe derivative of e7x is e7xln(7)
in respect to y 2y*3-y collecting the three times the coefficient of y which is 2 6y-y 6y-y=5y the derivative of 5y in respect to y is 5.
The derivative at a given point in a circle is the tangent to the circle at that point. To find the derivative of a circle you must use implicit differentiation. The equation of a circle: x^2 + y^2 = r^2 Take the derivative of both sides. Since r is always a constant, it does not matter what it is. The derivative of a constant is always zero, so the value of r will not affect the final answer for the derivative of a circle. 2x + 2y * dy/dx = 0 2y * dy/dx = -2x dy/dx = -2x/2y Simplify: dy/dx = -(x/y) The derivative of a circle of any radius at any point on that circle is -(x/y).
assuming that you are referring to a function: f(y) = y×y or better put: f(y) = y2 Then it's derivative would be: f'(y) = 2y
4x-2y+3x+2y When simplified: 7x
2y squared * y cubed= 2y^5 (2y to the fifth power)
-2y+y = -y
3x - 2y and 3x + 2y are in their simplest form. They don't factor.
-6x = 2y - 120 -2y -2y -2y - 6x = -120 +6x +6x -2y = 6x - 120 -2y/-2 = 6x/-2 - 120/-2 y = -3x + 60
"Derivative of"
Yes. It is like having a-b, which is a+(-b), which is -b+a, so 3-2y = 3+(-2y) = -2y+3
2y+8y2 can be factored to 2y(1+4y)
2y-10y