The derivate of 3x is 3; the derivative of -1 is 0. So, the derivative of 3x-1 is simply 3.The derivate of 3x is 3; the derivative of -1 is 0. So, the derivative of 3x-1 is simply 3.The derivate of 3x is 3; the derivative of -1 is 0. So, the derivative of 3x-1 is simply 3.The derivate of 3x is 3; the derivative of -1 is 0. So, the derivative of 3x-1 is simply 3.
If y = 3x +- 1, the derivative with respect to x is y' = 3.
3sec2(3x)
the derivative of 3x is 3 the derivative of x cubed is 3 times x squared
e^(-2x) * -2 The derivative of e^F(x) is e^F(x) times the derivative of F(x)
The derivate of 3x is 3; the derivative of -1 is 0. So, the derivative of 3x-1 is simply 3.The derivate of 3x is 3; the derivative of -1 is 0. So, the derivative of 3x-1 is simply 3.The derivate of 3x is 3; the derivative of -1 is 0. So, the derivative of 3x-1 is simply 3.The derivate of 3x is 3; the derivative of -1 is 0. So, the derivative of 3x-1 is simply 3.
d/dx e3x = 3e3x
f'(x)=-3the derivative of e is zero because its a constant. Derivative of -3x is -3. Bring the exponent of x down in front of the -3 and subtract the original exponent by 1. Ex. -3(1...which is the first exponent of the x)x^0(n-1 or 1-1=0)all this is -3(1)x^0x^0 is 1 so the derivative of -3x is -3
If y = 3x +- 1, the derivative with respect to x is y' = 3.
The derivative of y = sin(3x + 5) is 3cos(3x + 5) but only if x is measured in radians.
3sec2(3x)
3x - 4 sqrt(2)The first derivative with respect to 'x' is 3.
the derivative of 3x is 3 the derivative of x cubed is 3 times x squared
9x2
In this case, you'll need to apply the chain rule, first taking the derivative of the tan function, and multiplying by the derivative of 3x: y = tan(3x) ∴ dy/dx = 3sec2(3x)
int(e 3x) = (1/3)e 3x ========
-1