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Q: Derivative of y sin 3x 5?

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amplitude of the function y =-3 sin 3x

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To differentiate y=sin(sin(x)) you need to use the chain rule. A common way to remember the chain rule is "derivative of the outside, keep the inside, derivative of the inside". First, you take the derivative of the outside. The derivative of sin is cos. Then, you keep the inside, so you keep sin(x). Then, you multiple by the derivative of the inside. Again, the derivative of sinx is cosx. In the end, you get y'=cos(sin(x))cos(x))

If you mean: y-3x = 5 then in slope intercept form y = 3x+5

Related questions

If y = 3x +- 1, the derivative with respect to x is y' = 3.

y = 2 sin 3x y' = 2(sin 3x)'(3x)' y' = 2(cos 3x)(3) y' = 6 cos 3x

amplitude of the function y =-3 sin 3x

y= sin 3x

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Y=10^sin(x) The derivative is: (log(5)+log(2))*cos(x)*2^sin(x)*5^sin(x) Use the chain rule, product rule, and power rules combined with sin(x) rule.

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y=2 sin(3x) dy/dx = 2 cos(3x) (3) dy/dx = 6 cos(3x)

D(y)= sin 2x

To differentiate y=sin(sin(x)) you need to use the chain rule. A common way to remember the chain rule is "derivative of the outside, keep the inside, derivative of the inside". First, you take the derivative of the outside. The derivative of sin is cos. Then, you keep the inside, so you keep sin(x). Then, you multiple by the derivative of the inside. Again, the derivative of sinx is cosx. In the end, you get y'=cos(sin(x))cos(x))

If you mean: y-3x = 5 then in slope intercept form y = 3x+5

y = mx + b y-5 = 3x-1 y-5+5 = 3x-1+5 y = 3x + 4

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