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How do you differentiate y equal to one third x cubed minus 3x squared plus 8x plus one third?
The derivative of y = 1/3 x3 - 3x2 + 8x + 1/3 is x2 - 6x + 8. You can determine this for yourself by the rules. The derivative of a constant (e.g. 1/3) is 0. The derivative of xn for positive n (actually all nonzero n) is nxn-1. And if the derivative of f(x) is f'(x), then the derivative of k f(x) is k f'(x). Put all these together and you get the above result.
What is the derivative of 3x?
Let y = 3x y' = 3(x)' y' = 3(x1)' y' = 3[1x(1-1)] y' = 3(1x0) y' = 3(1 x 1) y' = 3 In general: y = xn y' nx(n-1)
Prove that a constant vector always has a perpendicular derivative?
A dot A = A2 do a derivative of both sides derivative (A) dot A + A dot derivative(A) =0 2(derivative (A) dot A)=0 (derivative (A) dot A)=0 A * derivative (A) * cos (theta) =0 => theta =90 A and derivative (A) are perpendicular
What is the derivative of e7x?
The derivative of e7x is e7 or 7e.The derivative of e7x is 7e7xThe derivative of e7x is e7xln(7)
What is the derivative of square root of 2?
the derivative is 0. the derivative of a constant is always 0.
What is the first derivative of X to the 23 power?
(x23)'=23x22 Generally, (xn)'=n*xn-1
What is newton-raphson formula for finding roots of non linear equations?
The Newton-Raphson method works if the equations are differentiable over the domain. Let f(x) be the non-linear equation and f'(x) by its derivative [with respect to x]. Start with a reasonable guess at the answer, x0. Then calculate the sequence xn+1 = xn - f(xn)/f'(xn) for n = 0, 1, 2, … The N-R method should converge to a root.
Sum of series 1 plus x2 plus x4.....plus xn?
(xn+2-1)/(x2-1)ExplanationLet Y=1+x2+x4+...+xn. Now notice that:Y=1+x2+x4+...+xn=x2(1+x2+x4+...+xn-2)+1Y+xn+2=x2(1+x2+x4+...+xn-2+xn)+1Y+xn+2=x2*Y+1Y+xn+2-x2*Y=1Y-x2*Y=1-xn+2Y(1-x2)=1-xn+2Y=(1-xn+2)/(1-x2)=(xn+2-1)/(x2-1)
Newtons iteration formula for finding square root of N?
xn+1 = 1/2 ( xn + N/xn )
Can you Factor completely xelevado a n - yelevado a n?
xn- yn=(x - y)(xn-1 + xn-2y +xn-3y2 +. . .+x2yn-3+xyn-2 + yn-1)
How do you differentiate y equal to one third x cubed minus 3x squared plus 8x plus one third?
The derivative of y = 1/3 x3 - 3x2 + 8x + 1/3 is x2 - 6x + 8. You can determine this for yourself by the rules. The derivative of a constant (e.g. 1/3) is 0. The derivative of xn for positive n (actually all nonzero n) is nxn-1. And if the derivative of f(x) is f'(x), then the derivative of k f(x) is k f'(x). Put all these together and you get the above result.
Find X when Y equals Xn?
Y=Xn Y/n=X
What monomial term has the form xn where the coefficient is a and the degree is n?
If by "xn" you mean ax^n then the answer is "a"
What is x to the power of the number that it is divided by?
This is represented as the algebraic expression xn/n or xn ÷ n.
Can you write any simple c program without header file?
Yes you (usually) can, though it may depend on your particular C implementation. // A complete (if useless) C program to compute the square root of 2 and then exit. // No headers required. double sqroot(const double s) { double xn = s / 2.0; double lastX = 0.0; while(xn != lastX) { lastX = xn; xn = (xn + s/xn) / 2.0; } return xn; } int main() { double sqrt2 = sqrt(2); return 0; }
How do you find the cubic root?
One way to find the square root of a number is an iterative method. This entails making a guess at the answer and then improving on it. Repeating the procedure should lead to a better estimate at each stage. One such method is the Newton-Raphson method. To start with, if you want to find the cube root if k, define f(x) = x3 - k. Then finding the cube root of k is equivalent to solving f(x) = 0. Let f'(x) = 3x2. This is the derivative of f(x) but that is not important for simply using the N-R method. Start with x0 as the first guess. Then let xn+1 = xn - f(xn)/f'(xn) for n = 0, 1, 2, … After a few iterations, xn will be very close to the required root.
What is the nth term of 87 83 78 72 65?
xn = xn-1 - (n + 2).
