The domain of the function f (x) = square root of (x - 2) plus 4 is Domain [2, ∞)
sqrt(x) Domain: {0,infinity) Range: {0,infinity) *note: the domain and range include the point zero.
The domain and the range depends on the context. For example, the domain and the range can be the whole of the complex field. Or I could define the domain as {-2, 1, 5} and then the range would be {0, 3, -21}. When either one of the range and domain is defined, the other is implied.
The domain could be the real numbers, in which case, the range would be the non-negative real numbers.
x = the domain y = the co-domain and range is the output or something e_e
The domain of the function f (x) = square root of (x - 2) plus 4 is Domain [2, ∞)
The answer depends on the domain for x. For example, if the domain is x = 7, then the range is 55. If the domain is all Real numbers, then the range is y >= 6.
It depends on the domain but, if the domain is the real numbers, so is the range.
The domain and range are both [-6, +6].
Y = x squared -4x plus 3 is an equation of a function. It is neither called a domain nor a range.
The range is {-7, 1, 9, 17}.
Domain (input or 'x' values): -∞ < x < ∞.Range (output or 'y' values): -2 ≤ y ≤ 2.
The domain can be anything you like as long as it excludes the point x = -40.The range is the set of all values that y can take for the values of x in the domain of your choice.
The domain is the whole real line (or complex plane).
(x^2)^(1/2) equals x, therefore, y = x+4, which has a range and domain of all real numbers. The graph is a straight line, slope of 1, y-intercept of 4. Are you actually saying y = (x^2+4)^(1/2). If so, the range and domain will also be all real numbers because x^2+4 will never result in a negative number.
y=x^2
sin(x)-cos(x) = (1)sin(x)+(-1)cos(x) so the range is sqrt((1)^2+(-1)^2)=1 and the domain is R <><><><><> The domain of sin x - cos x is [-infinity, +infinity]. The range of sin x - cos x is [-1.414, +1.414].