yes 1 + cot x^2 = csc x^2
The domain of the function f (x) = square root of (x - 2) plus 4 is Domain [2, ∞)
sqrt(x) Domain: {0,infinity) Range: {0,infinity) *note: the domain and range include the point zero.
The domain is what you choose it to be. You could, for example, choose the domain to be [3, 6.5] If the domain is the real numbers, the range is [-12.25, ∞).
The solution for cosec x equals 0 can be found by identifying the values of x where the cosecant function equals 0. Cosecant is the reciprocal of the sine function, so cosec x = 0 when sin x = 1/0 or sin x = undefined. This occurs at multiples of Ī, where the sine function crosses the x-axis. Therefore, the solutions for cosec x = 0 are x = nĪ, where n is an integer.
cosecant(x) = 1/sin(x)
The answer depends on what you mean by "vertical of the function cosecant". cosec(90) = 1/sin(90) = 1/1 = 1, which is on the graph.
One plus cosecant squared x is equal to cotangent squared x.
The period of the cosecant function is 2Ī, which means the graph of cosecant repeats every 2Ī units along the x-axis.
We're not sure how you wrote the question.If you wrote it as a subtraction: [ cosecant minus 1 ] = sine, then no, that's false.If you wrote it as an exponent: [ cosecant to the -1 power ] = sine, then yes, that's true.1 / csc(x) = sin(x)
cot(x) = sqrt[cosec^2(x) - 1]
No. The inverse of the secant is called the arc-secant. The relation between the secant and the cosecant is similar to the relation between the sine and the cosine - they are somehow related, but they are not inverse functions. The secant is the reciprocal of the cosine (sec x = 1 / cos x). The cosecant is the reciprocal of the sine (cos x = 1 / sin x).
It is 2*pi radians.
cosecant of C + cosecant of D = -2 sine of (C+D)/2 X sine of (C - D)/2
yes 1 + cot x^2 = csc x^2
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The domain is the (x) of the equation, and if (x) is zero then that is the domain. So yes the domain can be zero.