For most purposes the cosecant can be thought of as a function that assumes values over the entire real line. However, it is actually defined over the entire complex plane. Excepting, of course, points where the sine is zero.
Chat with our AI personalities
yes 1 + cot x^2 = csc x^2
The domain of the function f (x) = square root of (x - 2) plus 4 is Domain [2, ∞)
sqrt(x) Domain: {0,infinity) Range: {0,infinity) *note: the domain and range include the point zero.
The domain is what you choose it to be. You could, for example, choose the domain to be [3, 6.5] If the domain is the real numbers, the range is [-12.25, ∞).
The solution for cosec x equals 0 can be found by identifying the values of x where the cosecant function equals 0. Cosecant is the reciprocal of the sine function, so cosec x = 0 when sin x = 1/0 or sin x = undefined. This occurs at multiples of π, where the sine function crosses the x-axis. Therefore, the solutions for cosec x = 0 are x = nπ, where n is an integer.
cosecant(x) = 1/sin(x)
The answer depends on what you mean by "vertical of the function cosecant". cosec(90) = 1/sin(90) = 1/1 = 1, which is on the graph.
One plus cosecant squared x is equal to cotangent squared x.
The period of the cosecant function is 2π, which means the graph of cosecant repeats every 2π units along the x-axis.
We're not sure how you wrote the question.If you wrote it as a subtraction: [ cosecant minus 1 ] = sine, then no, that's false.If you wrote it as an exponent: [ cosecant to the -1 power ] = sine, then yes, that's true.1 / csc(x) = sin(x)
cot(x) = sqrt[cosec^2(x) - 1]
No. The inverse of the secant is called the arc-secant. The relation between the secant and the cosecant is similar to the relation between the sine and the cosine - they are somehow related, but they are not inverse functions. The secant is the reciprocal of the cosine (sec x = 1 / cos x). The cosecant is the reciprocal of the sine (cos x = 1 / sin x).
It is 2*pi radians.
cosecant of C + cosecant of D = -2 sine of (C+D)/2 X sine of (C - D)/2
yes 1 + cot x^2 = csc x^2
-240
The domain is the (x) of the equation, and if (x) is zero then that is the domain. So yes the domain can be zero.