For most purposes the cosecant can be thought of as a function that assumes values over the entire real line. However, it is actually defined over the entire complex plane. Excepting, of course, points where the sine is zero.
yes 1 + cot x^2 = csc x^2
The domain of the function f (x) = square root of (x - 2) plus 4 is Domain [2, ∞)
sqrt(x) Domain: {0,infinity) Range: {0,infinity) *note: the domain and range include the point zero.
The domain is what you choose it to be. You could, for example, choose the domain to be [3, 6.5] If the domain is the real numbers, the range is [-12.25, ∞).
x = the domain y = the co-domain and range is the output or something e_e
cosecant(x) = 1/sin(x)
The answer depends on what you mean by "vertical of the function cosecant". cosec(90) = 1/sin(90) = 1/1 = 1, which is on the graph.
One plus cosecant squared x is equal to cotangent squared x.
We're not sure how you wrote the question.If you wrote it as a subtraction: [ cosecant minus 1 ] = sine, then no, that's false.If you wrote it as an exponent: [ cosecant to the -1 power ] = sine, then yes, that's true.1 / csc(x) = sin(x)
cot(x) = sqrt[cosec^2(x) - 1]
No. The inverse of the secant is called the arc-secant. The relation between the secant and the cosecant is similar to the relation between the sine and the cosine - they are somehow related, but they are not inverse functions. The secant is the reciprocal of the cosine (sec x = 1 / cos x). The cosecant is the reciprocal of the sine (cos x = 1 / sin x).
It is 2*pi radians.
cosecant of C + cosecant of D = -2 sine of (C+D)/2 X sine of (C - D)/2
yes 1 + cot x^2 = csc x^2
-240
There is no minimum value for the cosecant function.
The domain is the (x) of the equation, and if (x) is zero then that is the domain. So yes the domain can be zero.