The domain of the function f (x) = square root of (x - 2) plus 4 is Domain [2, ∞)
f(t)dt and when f(t)=1=1/s or f(t)=k=k/s. finaly can be solve:Laplace transform t domain and s domain L.
The domain is what you choose it to be. You could, for example, choose the domain to be [3, 6.5] If the domain is the real numbers, the range is [-12.25, ∞).
Υou show that it is continuous in every element of it's domain.
The domain could be the real numbers, in which case, the range would be the non-negative real numbers.
Depends what f is....
The domain of f is x is R (if imaginary roots are permitted, and there is nothing in the question to suggest otherwise). The domain of g is R excluding x = 5 So the domain of f + g is R excluding x = 5 and the domain of f/g is R excluding x = 0
The domain of the function f (x) = square root of (x - 2) plus 4 is Domain [2, ∞)
The answer depends on the domain of f. With an unconstrained domain, the range is all real (or even complex) numbers.
If f(x) is the inverse of g(x) then the domain of g(x) and the range of f(x) are the same.
f(x)=5x Domain is any number for x that will provide a real number for f(x). In this function, x can be any real number, and f(x) will be a real number. Thus domain is all real numbers.
Yes.
The domain can be any subset of the set of all numbers.
11
5
The domain of x^3 - 2x is whatever you choose it to be. That will then determine the range.
f(x)=(x/|x-3|)+1; domain is all real numbers except 3. f(x)=(x/(|x-3|+1)); domain is all real numbers.