maximum value of 6y+10y
6x - 1 = 29 => 6x = 30 => x = 5 Then x2 + x = 25 + 5 = 30
d/dx (ln(6x)) = (d/dx (6x))/(6x) = 6/6x = 1/x
6X-5 = 31 (add 5 to both sides ) 6X = 36 ( divide both sides by 6 ) X = 6 ( check ) 6(6) -5 = 31 36-5 = 31 31 = 31
6x-3y
Since there is no feasible region defined, there is no answer possible.
The answer depends on the feasible region and there is no information on which to determine that.
(6x)(5y)
maximum value of 6y+10y
Given definitions, or descriptions at least, of "point D" and "the feasible region",I might have had a shot at answering this one.
y = -9
There is no possible value of 'x' for which (6x-2) can be equal to (6x-12).
6x od
3-6x = 15 -6x = 15-3 -6x = 12 x = -2
(-3,-1)
-6x - 5 + 10It's an algebraic expression in 'x'. It can be simplifiedby combining like terms:-6x + 5Its numerical value depends on the value of 'x'.
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