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Given definitions, or descriptions at least, of "point D" and "the feasible region",
I might have had a shot at answering this one.

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Q: What is the value of 6x 5y at point D in the feasible region?
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What is the minimum value of 6x plus 5y in the feasible region excluding point (0 0)?

The answer depends on the feasible region and there is no information on which to determine that.


What is the maximum value of 6x plus 5y in the feasible region?

(6x)(5y)


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Since there is no feasible region defined, there is no answer possible.


What is the minimum value of 3x plus 5y in the feasible region?

It is 18.


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What is the maximum value of 3x 5y in the feasible region?

The question cannot be answered because:there is no symbol shown between 3x and 5y,there is no information on the feasible region.The question cannot be answered because:there is no symbol shown between 3x and 5y,there is no information on the feasible region.The question cannot be answered because:there is no symbol shown between 3x and 5y,there is no information on the feasible region.The question cannot be answered because:there is no symbol shown between 3x and 5y,there is no information on the feasible region.


What is the minimum value of 3x plus 5y in the feasible region (07)(37)(63)(60)?

It is 18.


What is the value of x if 4x equals 5y?

If: 4x = 5y Then: x = 5y/4


Using the function f(x,y) =2x+ 5y determine the maximum value of the region if the point are (-2,3),(5,-3), and (1,4)?

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What is the y-intercept of 6x-5y15?

-3 Solution Method: ------------------ 1. Clarify the problem: What is the y-intercept of 6x-5y=15? 2. Recall what the "y-intercept" is: "the y-intercept is the y coordinate when the x value = 0 or the b value in the slope-intercept form (y = mx + b (b=the y-intercept value)) of the point-slope equation (y - y1 = m(x-x1). 3. Input the x coordinate into the equation & find the y value: 6(0)-5y=15 0-5y=15 -1/5 * -5y = 15 * -1/5 y = - 3 (this is your y-intercept value) OR when (y = mx + b), then b = the y-intercept value) 6x - 5y = 15 -6x - 5y = -6x + 15 -5y = -6x + 15 -1/5 * 5y = (-6x + 15) * -1/5 y = 6/5x - 3 (-3 = the y-intercept value) ================ A2. I am assuming you mean 6x - 5y = 15. Since the y intercept is at x=0, plugging x=0 into the equation gives 6(0)-5y=15. Since 6(0)=0, this gives -5y=15. Dividing both sides by -5 gives y=-3. Remember, the y-intercept is a point, so, since x=0, the point is (0,-3). A1?: ---------------------- Another way ---------------------- The equation is 6x - 5y = 15 The equation for graphing a line is y = mx + b where b is the y-intercept. Try to get it in this form - 6x - 5y = 15 (Add 5y on both sides) 6x = 15 + 5y (Subtract 15 from both sides) 6x - 15 = 5y (Since we need to get a single y, divide both sides by 5) (6x)/5 - (15)/5 = (5y)/5 (Simplify) 6/5x - 3 = y Therefore, the slope is 6/5 and the y intercept is -3. Good luck!


What is the value of 5y-2y?

7