1
3x+5y=48 5y=48-3x-3x+5y=12 -3x+(48-3x)=12-6x=-36x=65y=48-3(6)5y=30y=6(6,6)
-3+(-5)2=22
3x+4=10 To solve: 3x+4=10 3x=6 x=2
3x-2 = 2x+3 3x-2x = 3+2 x = 5
Add 5 to both sides of the equation to get rid of the - 5. -3x - 5 + 5 = -20 + 5 Solve and simplify. -3x = -15 Divide both sides of the equation by -3. x = 5
There are an infinite number of ordered pairs that satisfy the equation.
x = 5 and y = 4
Any pair of numbers at all, as long as one of them is triple the other one.
y=3x
y = 3x =3(6) = 18 ... the ordered pair is (x,y) = (6,18)
3x
The ordered pair is (5, 4).
3x + 4y = -4 defines a line in 2-dimensional space and the coordinates of every point on the line is an ordered pair that satisfies the equation. I have neither the time nor the inclination to list an infinite number of ordered pairs.
{-4,-5}
Without an equality sign it can not be considered to be an equation and the - or + values of y and 12 are not given
really depends. 12x - 8y = 48 3x - 2y = 12. You can't decide, but one ordered pair is (4,0)
Substitute the value for y given by the second equation into the first equation to result in 3x - 15 = x2 - x -20. Subtract (3x - 15) from both sides and exchange sides to yield x2 - 4x - 5 = 0. This can be factored into (x - 5)(x + 1) = 0, which is true when x equals either 5 or -1. If x = 5, y = 0 and if x = -1, then y = -18. Therefore, either 5,0 or -1,-18 is an ordered pair solution to the given equation system.