Points: (1, 1) and (3, 15)
Slope: 7
this is an equation of a line. it has a slope of 4/3 and a y-intercept of 5
(3/4, 0) and (5/2, 0) Solved with the help of the quadratic equation formula.
f(x) = -x3 + 9x2 - 15x - 10 => df/dx = -3x2 + 18x - 15 = -3*(x - 1)*(x - 5) df/dx = 0 => x = 1 or x = 5 So, the stationary points are x = 1 and x = 5
The first thing you need to do is get this equation to y=something, here's how you'd work that for this equation. 15x-5y=30 (subtract 15x from both sides) 5y=-15x+30 (now we're going to divide everything by 5 to get y by itself) y=-3x+6 The graph of this equation is going to be a straight line with a slope of -3 and a y-intercept of 6 * * * * * Here is a simpler way. You do not have to rewrite the equation. Just leave it as it is: 15x - 5y = 30 Step 1A: Cover up the y term so that the equation reads: 15x = 30 divide both sides by 15 so you get x = 2. Step 1B: Mark the point with coordinates x = 15, y = 0 ie (15, 0), and label it A. Step 2A: Cover up the x term so that the equation reads: -5y = 30 divide both sides by -5 so you get y = -6. Step 2B: Mark the point with coordinates x = 0, y = -6 ie (0, -6) and label it B. Step 3: Join AB and extend both ways. Step 4: Sit back and laugh at the people who rewrote the formula in the form y = something, got the slope and intercept, but don't know how that helps to graph the equation!
5x = 15 so x = 15/5 = 3
Points: (-1, -1) and (3, 15) Slope: 4
Points: (0, 5) and (10, -15) Slope: -2
Points: (3, 15) and (5, 9) Slope: -3
Points: (15, 8) and (7, 3) Slope: 5/8
Points: (10, 8) and (15, 8) Slope: 0 It will be a straight horizontal line
Slop between (x1, y1) and (x2, y2) is given by: slope = y_difference / x_difference = (y2 - y1) / (x2 - x1) For (-1, -1) to (3, 15): slope= (15 - -1) / (3 - -1) = 16 / 4 =4
slope is =( 9-15 )/ (5-3) = -6/2 = -3
If you mean points of (1, 5) and (-2, -4) then the slope works out as 3
If you mean points of (1, 5) and (-1, -1) then the slope works out as 3
The slope of the line that passes through the points (3,15) and (5,9), is -3; use the formula change in Y-axis/change in X-axis.
If you mean a slope of 2/5 and the point (-15, 12) then equation is 5y = 2x+90
The idea is to divide (difference in y-coordinates) by (difference in x-coordinates). If you mean points of (-5, 4) and (15, -4) then the slope works out as -2/5