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Beaux2 - 1 is not a perfect square and thus does not have a square root. It does have two factors though, and those would be (x - 1) and (x + 1).
*** if x2-1 is in the square root symbol [also (x2-1)-2 ], you would end up with x+1-2 throught the process of distribution. (which is the same as saying the square root of 1)
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What is 1 minus cos squared?
sin squared
Factor x squared plus x minus 10?
to factor this equation you need to use the quadratic formula:in this question a=1, b=1, c= -10so after you plug in those number you answer would be:x= (-1+ or - the square root of -39) divided by 2
What does x equal if x square equals -3?
If you want to work with real numbers, there is no answer. the square of any number, whether positive or negative, is a positive number, so x2 cannot be -3. If you accept complex numbers as a solution, the square root of minus 1 is called i (when squared, both i and -i give -1); the square root of -3 is equal to the square root of 3 times i, the square root of -4 is 2i, etc. Complex numbers are frequently used in some areas of science (electricity, quantum mechanics, and others); in other areas, it just doesn't make sense to use them. Similarly, for some problems fractional solutions, or negative solutions, may be acceptable, for others, not.
Solve this quadratic equation using the quadratic formula x2 - 6x 6 0?
if this is x squared -6x+6=0 then -6=b, a=1, c=6 6+ square root of -6 squared-4(6x1) - 6+ square root of (36-24) - 6+ square root of 12 - 6+ square root of 4 x square root of 3 - 6 + (2x square root of 3) - that is all divided by 2 multiplied by a meaning it is divided by 2. so x= 6 + or - (2 square root 3) divided by 2 srry steps are jmbled -
How can you solve the equation x2 plus 3i equals 0?
x2+3i=0 so x2=-3i x=square root of (-3i)=square root (-3)square root (i) =i(square root(3)([1/(square root (2)](1+i) and i(square root(3)([-1/(square root (2)](1+i) You can multiply through by i if you want, but I left it since it shows you where the answer came from. Note: The square root of i is 1/square root 2(1+i) and -1/square root of 2 (1+i) to see this, try and square them!
