to factor this equation you need to use the quadratic formula:
in this question a=1, b=1, c= -10
so after you plug in those number you answer would be:
x= (-1+ or - the square root of -39) divided by 2
The expression 2x squared minus x squared simplifies to x squared. This is because when subtracting like terms, you subtract the coefficients while keeping the variable and its exponent the same. In this case, 2x squared minus x squared leaves you with just x squared.
21
what two numbers multiply to 24 and add to -10? -4 and -6 look good, so: (x - 4)(x - 6) x = 4 or 6
The domain is what you choose it to be. You could, for example, choose the domain to be [3, 6.5] If the domain is the real numbers, the range is [-12.25, ∞).
(g + 5)(g + 2)
(5x - 2)(x - 5)
20x2 - 3x + 10 does not have any real factors.
x2+2x-120 = (x+12)(x-10) when factored
The factors are [3x + 5 - 2*sqrt(10)] and [3x 5 + 2*sqrt(10)].
n2 - 100 = (n + 10)(n - 10)
2
10x^2 - x - 2 = (5x + 2)(2x - 1)
(3x-2)(x-2)
(x + 5)(x + 2)
That doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: (-5 plus or minus the square root of -15) divided by 2.x = -2.5 + 1.9364916731037085ix = -2.5 - 1.9364916731037085iwhere i is the square root of negative one.
(3r + 2)(r - 5)
(11x - 2)(3x - 5)