to factor this equation you need to use the quadratic formula:
in this question a=1, b=1, c= -10
so after you plug in those number you answer would be:
x= (-1+ or - the square root of -39) divided by 2
Oh, dude, that's like basic math 101. So, 2x squared minus x squared is just x squared. It's like when you have two pizzas and you take away one pizza, you're left with just one pizza, right? Same idea here, just with algebra instead of pepperoni.
21
The domain is what you choose it to be. You could, for example, choose the domain to be [3, 6.5] If the domain is the real numbers, the range is [-12.25, ∞).
7x + 8 = 10x - 2 ∴ 3x = 10 ∴ x = 10/3
(g + 5)(g + 2)
(5x - 2)(x - 5)
20x2 - 3x + 10 does not have any real factors.
x2+2x-120 = (x+12)(x-10) when factored
The factors are [3x + 5 - 2*sqrt(10)] and [3x 5 + 2*sqrt(10)].
2
n2 - 100 = (n + 10)(n - 10)
10x^2 - x - 2 = (5x + 2)(2x - 1)
(3x-2)(x-2)
(x + 5)(x + 2)
That doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: (-5 plus or minus the square root of -15) divided by 2.x = -2.5 + 1.9364916731037085ix = -2.5 - 1.9364916731037085iwhere i is the square root of negative one.
(3r + 2)(r - 5)
(11x - 2)(3x - 5)