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What is the vertex of the graph of y 3(x - 1)2 2?
The vertex of the graph Y 3 X-12 plus 2 would be -1/3 and -4/3. This is taught in math.
How do you find a midpoint between two points on a graph?
Given two coordinates (x1,y1) and (x2,y2) The midpoint is ( ((x2+x1)/2) , ((y2+y1)/2) )
What is the vertex of the graph y-2x2 8x-3?
y=-2x^2+8x+3
How can you find the length of a line segment in the coordinate plane?
The formula is the square root of: (x2-x1)^2 plus (y2-y1)^2
What is the vertex of a polygon?
A vertex of a polygon is where 2 sides meet
What is the vertex of the graph of y 3(x - 1)2 2?
The vertex of the graph Y 3 X-12 plus 2 would be -1/3 and -4/3. This is taught in math.
What degree of a vertex would lead to a vertex edge graph unable to be traveled?
2
What is y equals x2 plus 2x plus 1 on a graph?
Interpreting that function as y=x2+2x+1, the graph of this function would be a parabola that opens upward. It would be equivalent to y=(x+1)2. Its vertex would be at (-1,0) and this vertex would be the parabola's only zero.
How you graph the slope on a graph?
you need 2 points on the line y2-y1 slope=----- x2-x1
What is the chromatic number of an n-vertex simple connected graph which does?
2
How do you find a midpoint between two points on a graph?
Given two coordinates (x1,y1) and (x2,y2) The midpoint is ( ((x2+x1)/2) , ((y2+y1)/2) )
The distance between points x1 y1 and 5 -5 is the square root of x1 plus 5 2 plus y1 - 52?
false
What is the formula for distance between two endpoints on a graph?
Distance between the two points (x1 , y1) and (x2 , y2) is square root of [ (y2 - y1)2 + (x2 - x1)2 ]
What is the vertex of y equals x-3 plus 2?
The equation is linear and so has no vertex.
Vertex of graph x2-6x plus 5?
y=aX2+bX+c ---> y=X2-6X+5vertex formula is -b/2a( b=-6,a=1)vertex=-(-6)/2*1=6/2=3 y=32-6(3)+5---->y=-4so vertex is (3,4)
Where is the vertex of the graph of y equals x2 plus 2x plus 5 located?
We need to complete the square to find the vertex of this parabola. X^2 + 2X + 5 = 0 X^2 + 2X = -5 halve the coefficient of the linear term ( 2X ) and square it perfectly and add to other side (X + 1)^2 = -5 + 1 (X + 1)^2 = -4 (X + 1)^2 + 4 = 0 Vertex is.... X = -1 Y = 4
Which way does the graph open when 'a' is positive?
When 'a' is positive in a quadratic function of the form (y = ax^2 + bx + c), the graph opens upwards. This means the vertex of the parabola is the lowest point on the graph, and as you move away from the vertex in either direction, the values of (y) increase.
