The vertex of the graph Y 3 X-12 plus 2 would be -1/3 and -4/3. This is taught in math.
Given two coordinates (x1,y1) and (x2,y2) The midpoint is ( ((x2+x1)/2) , ((y2+y1)/2) )
formula for the midpoint of a line
y=-2x^2+8x+3
The formula is the square root of: (x2-x1)^2 plus (y2-y1)^2
The vertex of the graph Y 3 X-12 plus 2 would be -1/3 and -4/3. This is taught in math.
2
Interpreting that function as y=x2+2x+1, the graph of this function would be a parabola that opens upward. It would be equivalent to y=(x+1)2. Its vertex would be at (-1,0) and this vertex would be the parabola's only zero.
you need 2 points on the line y2-y1 slope=----- x2-x1
2
Given two coordinates (x1,y1) and (x2,y2) The midpoint is ( ((x2+x1)/2) , ((y2+y1)/2) )
false
Distance between the two points (x1 , y1) and (x2 , y2) is square root of [ (y2 - y1)2 + (x2 - x1)2 ]
The equation is linear and so has no vertex.
y=aX2+bX+c ---> y=X2-6X+5vertex formula is -b/2a( b=-6,a=1)vertex=-(-6)/2*1=6/2=3 y=32-6(3)+5---->y=-4so vertex is (3,4)
We need to complete the square to find the vertex of this parabola. X^2 + 2X + 5 = 0 X^2 + 2X = -5 halve the coefficient of the linear term ( 2X ) and square it perfectly and add to other side (X + 1)^2 = -5 + 1 (X + 1)^2 = -4 (X + 1)^2 + 4 = 0 Vertex is.... X = -1 Y = 4
formula for the midpoint of a line