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What is the y-coordinate of the vertex of a parabola with the following equation y equals x2 - 8x plus 18?
Wiki User
∙ 12y ago
You can work this out by taking the derivative of the equation, and solving for zero:
y = x2 - 8x + 18
y' = 2x - 8
0 = 2x - 8
x = 4
So the vertex occurs where x is equal to 4. You can then plug that back into the original equation to get the y-coordinate:
y = 42 - 8(4) + 18
y = 16 - 32 + 18
y = 2
So the vertex of the parabola occurs at the point (4, 2), leaving 2 as the answer to your question.
Wiki User
∙ 12y ago
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An equation of a parabola that has x equals 2 as its axis of symmetry is?
How about y = (x - 2)2 = x2 - 4x + 4 ? That is the equation of a parabola whose axis of symmetry is the vertical line, x = 2. Its vertex is located at the point (2, 0).
What is the vertex of a parabola whose equation is y equals x 32?
The given equation is not that of a parabola since there are no powers of 2. Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. And using ^ to indicate powers (eg x-squared = x^2).
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An equation of a parabola that has x equals 2 as its axis of symmetry is?
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