The domain of y = x2 is [0,+infinity]
x1:y1 = x2:y2 4:-2 = x2:5 x2 = (4*5)/-2 x2 = -10
the graph is moved down 6 units
Y = X2 forms a parabola
y = x2 - 6x + 2 y = x2 - 6x + 9 - 7 y = (x - 3)2 - 7
The domain of y = x2 is [0,+infinity]
If you mean y = x2, then yes, it is nonlinear.
x1:y1 = x2:y2 4:-2 = x2:5 x2 = (4*5)/-2 x2 = -10
No translation will invert a quadratic graph.
the graph is moved down 6 units
y = 4x-3
Y = X2 forms a parabola
Yes. Think of y as being a function of x. y = f(x) = x2 + 1
y = x2 + 4 The graph is a parabola, with its nose at y=4 on the y-axis, and opening upward.
y = x2 - 6x + 2 y = x2 - 6x + 9 - 7 y = (x - 3)2 - 7
x2 / y = (6)2 /2 = 36/2 = 18
If: y = x2+20x+100 and x2-20x+100 Then: x2+20x+100 = x2-20x+100 So: 40x = 0 => x = 0 When x = 0 then y = 100 Therefore point of intersection: (0, 100)