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Oh, dude, like, that's just x, man. When you divide x² by x, you're basically just subtracting the exponents, which leaves you with x to the power of 1. So, yeah, x. Easy peasy lemon squeezy.
What is x squared divided by x?
x2 divided by x would simply be x.
What is the anti derivative of x divided by x squared minus 1?
The antiderivative of x/(x2-1) is ln(x2-1)/2. Proof: (ln(x2-1)/2)' = (1/(x2-1))*(x2-1)'/2=1/(x2-1)*(2x/2)=x/(x2-1).
What is the answer to x squared minus 16 divided by x minus 4 plus x squared equals 16?
Your equation is not clear I can understand it in two ways (x2-16)/x-4+x2=16 x=-4.59486 x=-0.793499 x=4.38835 or x2-(16/x)-4+x2=16 x=3.50466 x=-0.864641 x=-2.64002
What is X3 plus X2 plus X plus 1 divided by X 1?
2x2+7/x1
What is - x divided by x squared minus 1?
Do you mean: - x / (x2 - 1)? If so, that's as simplified as you can get. (- x / x2) - 1? If so, that simplifies to (-1/x) - 1. (-x/x)2 - 1? If so, that simplifies to 0. -(x/x)2 - 1? If so, that simplifies to -2. Or perhaps that dash in the question is actually a hyphen, in which case: x / (x2 - 1)? If so, that's also as simplified as you can get. (x / x2) - 1? If so, that simplifies to (1/x) - 1. (x/x)2 - 1? If so, that simplifies to 0.
What is x squared divided by x?
x2 divided by x would simply be x.
What is x squared divided by -x?
x2/(-x) = -x.
What is x divided by x cubed?
1/x2
What is X2 divided by -4x?
6
What is 3x4 plus 5x3 plus x2 - 5 divided by x 2?
3x4 plus 5x3 plus x2 - 5 divided by x 2 =[(3x4) + (5x3) + (x2 - 5)]/x2 =(12 + 15 + x2 -5)/x2 =(27 - 5 + x2)/x2 =(22 + x2)/x2
What is X cubed divided by X?
X2 (X squared)
What is x2 divided by x-2?
4
What is the value of x2 divided by x?
x= x2/x= x
X2 equals 5 what is the value of x?
if x2 = 5 the value of x has to be 5 divided by 2 which is 2.5 x = 2.5
What is x divided by 2 x2?
x ÷ 2x2 = 1/2x
What is the derivative of 4 divided by X?
-4/x2
What is the remainder when x2 plus 4 is divided by x-2?
The remainder is 8. (x2 + 4)/(x - 2) = (x + 2) + 8/(x - 2) or x2 + 4 = (x - 2)(x + 2) + 8
