x2 + 4x + 3 = (x + 1)(x + 3)
Dividend: x3+4x2-9x-36 Divisor: x+3 Quotient: x2+x-12
x2-12x+36 = (x-6)2
if x2 + 7 = 37, then x2 = 29 and x = ±√29
The question is ambiguous and two possible answers are given below: 2x2 - x2 = x2 or (2x)2 - x2 = 4x2 - x2 = 3x2
x2 + 7x - 56 cannot be factorised.
x4 - x3 - x - 1 rewriting: = x4 - 1 - x3 - x factorising pair of terms: =(x2 + 1)*(x2 - 1) - x*(x2 + 1) = (x2 + 1)*(x2 - 1 - x) or (x2 + 1)*(x2 - x - 1) which cannot be factorised further.
3x2 - 15x + 42 = 3*(x2 - 5x + 14) which cannot be factorised further.
(x-4)
x2-5x-36 = (x-9)(x+4) when factored
(x-9)(x+1)
x2 - 41 cannot be factorised.
(x-6)(x+3)
(x + 7)(x - 9)
=>2x - 12x + 36 = 0 =>10x = 36=>x = 3.6Another contributor's answer:This is a quadratic equation question:x2-12x+36 = 0When factorised:(x-6)(x-6) = 0
x2-9x+18 = (x-3)(x-6) when factorised
x2 + 4x + 3 = (x + 1)(x + 3)