X^3 - X^2 - 2X =0
factor out the X
X(X^2 - X - 2)
X(X + 2)(X-1)
fully factored
X = 0
X = -2
X = 1
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x2 + 4x + 3 = (x + 1)(x + 3)
If that was 2x^2 + 5x + 2, it would factor to (2x + 1)(x + 2)
2 X 2 - x - 6 = 04 -6 - x = 0- x = 2x = -2Another contributor's answer:This appears to be a quadratic equation question in form of:2x2-x-6 = 0When factorised:(2x+3)(x-2) = 0Therefore: x = -3/2 or x = 2
x^(2) - 36 = x^(2) - 6^(2) Remember two squared terms , as above, with a NEGATIVE between them can factor to (x - 6)(x + 6) NB #1 ; The different signs in the brackets. #2, Two squared terms with a POSITIVE (+) between them, does NOT factor. #3 ; Inspect the constant, to see if it is a squared number ; 36 = 6^(2) in this case.
Oh, what a happy little math problem we have here. To factorise x squared plus 7x, we can first look for a common factor, which in this case is x. So, we can factor out an x to get x(x + 7). And just like that, we've created a lovely little factorised expression.