its just a line, there are many answers that would work -12x-6y=0 -12x=6y x=-y/2 y=-2x
It simplifies to: 12x+3y
Solving these simultaneous equations by the elimination method:- x = 1/8 and y = 23/12
Substitute 2x - 6 for y in first equation: 12x - 5(2x - 6) = 30 ie 12x - 10x + 30 = 30 so 2x = 0 making x = 0 and y = -6
You can find the x-coordinate of it's vertex by taking it's derivative and solving for zero: y = -3x2 + 12x - 5 y' = -6x + 12 0 = -6x + 12 6x = 12 x = 2 Now that we have it's x coordinate, we can plug it back into the original equation to find it's y coordinate: y = -3x2 + 12x - 5 y = -3(2)2 + 12(2) + 5 y = -12 + 24 + 5 y = 17 So the vertex of the parabola y = -3x2 + 12x - 5 occurs at the point (2, 17).
6y
17
-2
1 and 3
y = x2 + 12x + 21At the max or min point, the first derivative of the function = 0.2x + 12 = 02x = -12x = -6
(-3, -5)
y = - 4x - 4
15
It's an inconsistent pair of equations, for which there is no solution.
No solution. Multiply second equation by 3 and get 12x + 6y = 0 but already stated 12x + 6y = 9...
The answer is y=0 .
15 (x = 135)