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X = 8

x2

(8)2

= 64

====

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Q: When x 8 what is the value of x2?
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Continue Learning about Calculus

What is x2 -6x 8 factored?

x2-6x+8 = (x-2)(x-4) when factored


If x2 plus 10x-33.33 equals 0 find the value of x?

x2+10x-33.33 = 0 Using the quadratic equation formula will give you two solutions which are: x = -12.63740794 to 8 decimal places. or: x = 2.63740794 to 8 decimal places


What are the solutions for the quadratic equation x2 plus 6x equals 16?

x2 + 6x = 16=> x2 + 6x - 16 = 0=> x2 + 8x -2x - 16 = 0=> (x+8)(x-2) = 0=> x = -8 or x = 2So, the solutions of the quadratic equation x2 + 6x = 16 are -8 and 2.


What is minus 1 times x squared?

The answer is -x2.A fuller explanation is as follows:Where letter X is an unknown value, -1 times Xsquared ( -1 x X2 )is just a general statement about X and would be more properly written as -X2.If we substitute say 2 as the value of X then -X2 = -2 x -2,now both (2 x 2) and (-2 x -2) = 4thus both -1 x X2 or -X2 = 4From the above you can see that what "minus 1 times x squared" is equal to depends upon the value of the letter x or X as I have written it to avoid confusion with the "times" sign usually written as x.


Consider an isosceles triangle whose two equal sides are of length 4 What is the largest possible area for such a triangle?

An isosceles triangle with side length 4 has an altitude x. By the Pythagorean theorem, the base of the triangle is 2*SQRT(16-x2). The area of the triangle is 1/2 base times height, so A=x*(16-x2)1/2. the derivative, dA/dx=(16-x2)1/2 - x2/(16-x2)1/2. This is found with the product rule and chain rule. This shows the rate which the area of the triangle changes with respect to the altitute. At the x value of the maximum, the area will have stopped increasing and begun to decrease, so the rate of increase wil be zero. We just need to solve for x. (16-x2)1/2 - x2/(16-x2)1/2=0 (16-x2)1/2=x2/(16-x2)1/2 (16-x2)=x2 16=2x2 8=x2 SQRT(8)=x. Now we can solve the original equation for the maximum are. SQRT(8)*SQRT(16-8) SQRT(8)*SQRT(8)=8 So 8 is the largest possible area.