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X plus y plus z squared?
If th equestion meant: (x+y+z)^2The expansion is:(x+y+z)^2= x^2+2xy+y^2+2yz+z^2+2zx
If xy plus y equals z then x equals?
xy + y = z xy = z - y (xy)/y = (z - y)/y x = (z - y)/y
What is the ordered triple of x plus y plus z equals 12 and y equals 1 and x-y-z equals 0?
x + y + z = 12 y = 1 x - y - z = 0 Substitute y = 1 in the other two equations: x + 1 + z = 12 so that x + z = 11 and x - 1 - z = 0 so that x - z = 1 Add these two equations: 2x + 0z = 12 which implies that x = 6 and then x + z = 11 gives z = 5 So the solution is (x, y, z) = (6, 1, 5)
What is x plus y to the second power plus z to the second power?
(x+y)^2+z^2=x^2+y^2+z^2+2xy or ((x+y)^2+z)^2= (x^2+y^2+2xy+z)^2= x^4+y^4+z^2+6x^2y^2+4x^3y+2x^2z^2+4xy^3+4xyz^2+2z^2y^2
Z2 equals x2 plus y2?
What are we solving here for, Z, X, or Y?If solve for Z then the answer would be z = x + yIf solve for X then the answer would be z = z - yIf solve for Y than the answer would y = z - xHope this help.
What is the property x plus y plus z equals x plus z plus y?
x + y + z = x + z + y is the commutative property of addition.
X plus y plus z squared?
If th equestion meant: (x+y+z)^2The expansion is:(x+y+z)^2= x^2+2xy+y^2+2yz+z^2+2zx
How do you factor a trinomial in two variables like y2-6yz plus 5z2?
(y - z)(y - 5z)
What is answers z plus y plus x?
That depends on the values of 'z', 'y', and 'x'.
True or false x plus 2y plus 3z is equivalent to z plus y plus z plus x plus y plus z?
True
If x plus y plus z equal 84 and x plus z equals 72 and x plus y equals 52 solve what is x what is y what is z?
y=84-72=12 z=84-52=32 x=84-12-32=40
What is the min value of 1 by x plus 1 by y plus 1 by z equal30 when x y and z are positive and x plus y plus z equal 30?
(1/x) + (1/y) + (1/z) is a minimum value when x=y=z=10. Symmetry gives either maximum or minimum value.
Is x plus y equals y plus x the associative property?
No, this is the commutative property. For addition, the associative property is: x + (y + z) = (x + y ) + z
If xy plus y equals z then x equals?
xy + y = z xy = z - y (xy)/y = (z - y)/y x = (z - y)/y
If x equals a-b y equals b-c z equals c-a then the value of x plus y plus z x plus y plus z is?
x + y + z = 0 x = a - b, y = b - c, z = c - a, therefore a - b + b - c + c - a = ? a - a + b - b + c - c = 0
How many variables are in this number 2 plus x plus y plus 6 plus z plus equals 9?
(2+x+y+6+z) += 9x,y and z are variables, there are 3.
X plus y plus z equals 9 and x plus 2y plus 3z equals 23 and x plus 5y-3Z equals -7 solve for x and y and z?
Can you help with this equation? Thanks. Solve for x and y and z for the following. x plus y plus z equals 9 x plus 2y plus 3z equals 23 x plus 5y plus -3z equals -7
