logx(3) = log10(7) (assumed the common logarithm (base 10) for "log7") x^(logx(3)) = x^(log10(7)) 3 = x^(log10(7)) log10(3) = log10(x^(log10(7))) log10(3) = log10(7)log10(x) (log10(3)/log10(7)) = log10(x) 10^(log10(3)/log10(7)) = x
log10(225)2 equals 5.5327625985087111
pH means -log10(H+concentration) so pH of a H+ concentration 3.6x10-9 is: pH = -log10(3.6x10-9) ≈ 8.4
Say you have some integer a. aFirst take it's absolute value. |a|Next log it base 10. log10 |a|Truncate this value, then add 1. trunc ( log10 |a| ) + 1You now have the number of digits.
The natural logarithm is calculated to base e, where e is Euler's constant. For any number, x loge(x) = log10(x)/log10(e)
logx(3) = log10(7) (assumed the common logarithm (base 10) for "log7") x^(logx(3)) = x^(log10(7)) 3 = x^(log10(7)) log10(3) = log10(x^(log10(7))) log10(3) = log10(7)log10(x) (log10(3)/log10(7)) = log10(x) 10^(log10(3)/log10(7)) = x
log10(225)2 equals 5.5327625985087111
4
There is no simple answer. 10 to the power 1.995635 (approx) = 99 The number 1.995635 is log10(99)
pH means -log10(H+concentration) so pH of a H+ concentration 3.6x10-9 is: pH = -log10(3.6x10-9) ≈ 8.4
log10 0 is actually undefined. Think about it like this: If loba b = y then we know that ay = b This means that log10 0 = y translates to 10y = 0 But as you know, 10y is always greater than zero. Therefore 10y = 0 is undefined. Therefore log10 0 = y is undefined.
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Let us assume you have a Hydrochloric acid solution of 0.1 M. The pH is - log10[H+]. So log10[0.1] = -1 easy way to remember this is 103 =1000 log 101000 = 3 102 =100 log 10100 = 2 101 =10 log 1010 = 1 100 =1 log 101 = 0 10-1 =0.1 log 100.1 = -1 10-2 =0.01 log 100.01 = -2 So log10[0.1] = -1 and thus pH is - log10[H] = (minus minus 1) = 1
xlog10 = x This is a simple rule of logs, because log(base10)10 = 1. Any value multiplied by one equals itself. So pi*log10 = pi(1) = pi.
pH = -log10[H+] = -log10(0.001 mol/L )= -log10(10-3)= 3
ln(x) = log10(X)/log10(e)
One possible answer is log(330) Another is 1 + log(33)