The logarithm function is defined so that if
y = 10x then log y = x
So, if x = 1, y = 101 = 10
and so log 10 = 1
logx(3) = log10(7) (assumed the common logarithm (base 10) for "log7") x^(logx(3)) = x^(log10(7)) 3 = x^(log10(7)) log10(3) = log10(x^(log10(7))) log10(3) = log10(7)log10(x) (log10(3)/log10(7)) = log10(x) 10^(log10(3)/log10(7)) = x
log10(225)2 equals 5.5327625985087111
pH means -log10(H+concentration) so pH of a H+ concentration 3.6x10-9 is: pH = -log10(3.6x10-9) ≈ 8.4
The logarithm base 10 (log10) of 0.00000001 can be calculated as follows: 0.00000001 is equivalent to 10^-8. Therefore, log10(0.00000001) = log10(10^-8) = -8.
The logarithm base 10 of 3160, denoted as log10(3160), is approximately 3.499. This value indicates that 10 raised to the power of about 3.499 equals 3160. You can calculate it using a scientific calculator or logarithm tables for more precise results.
logx(3) = log10(7) (assumed the common logarithm (base 10) for "log7") x^(logx(3)) = x^(log10(7)) 3 = x^(log10(7)) log10(3) = log10(x^(log10(7))) log10(3) = log10(7)log10(x) (log10(3)/log10(7)) = log10(x) 10^(log10(3)/log10(7)) = x
log10(225)2 equals 5.5327625985087111
4
There is no simple answer. 10 to the power 1.995635 (approx) = 99 The number 1.995635 is log10(99)
pH means -log10(H+concentration) so pH of a H+ concentration 3.6x10-9 is: pH = -log10(3.6x10-9) ≈ 8.4
The logarithm base 10 (log10) of 0.00000001 can be calculated as follows: 0.00000001 is equivalent to 10^-8. Therefore, log10(0.00000001) = log10(10^-8) = -8.
log10 0 is actually undefined. Think about it like this: If loba b = y then we know that ay = b This means that log10 0 = y translates to 10y = 0 But as you know, 10y is always greater than zero. Therefore 10y = 0 is undefined. Therefore log10 0 = y is undefined.
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The logarithm base 10 of 3160, denoted as log10(3160), is approximately 3.499. This value indicates that 10 raised to the power of about 3.499 equals 3160. You can calculate it using a scientific calculator or logarithm tables for more precise results.
Let us assume you have a Hydrochloric acid solution of 0.1 M. The pH is - log10[H+]. So log10[0.1] = -1 easy way to remember this is 103 =1000 log 101000 = 3 102 =100 log 10100 = 2 101 =10 log 1010 = 1 100 =1 log 101 = 0 10-1 =0.1 log 100.1 = -1 10-2 =0.01 log 100.01 = -2 So log10[0.1] = -1 and thus pH is - log10[H] = (minus minus 1) = 1
xlog10 = x This is a simple rule of logs, because log(base10)10 = 1. Any value multiplied by one equals itself. So pi*log10 = pi(1) = pi.
pH = -log10[H+] = -log10(0.001 mol/L )= -log10(10-3)= 3