A precise answer would require knowing the ambient temperature, the temperature of the water at the start, and the conductive properties of the vessel containing the water.
To calculate the BTUs needed to raise the temperature of a 40-gallon water heater by 60 degrees Fahrenheit, you can use the formula: BTUs = gallons × temperature rise × 8.34. For a 40-gallon heater, it would be 40 gallons × 60°F × 8.34 BTU/gallon°F, resulting in approximately 20,016 BTUs. Therefore, it takes about 20,016 BTUs to achieve that temperature increase.
A romm 20x9 is 180 square feet. You will need 5000 to 6000 BTUs for this.
About 114,000 BTU per US gallon.
The specific heat of water is 1 BTU per pound per degree Fahrenheit. There are 8.3378 lbs/gallon at 60 degrees, which equals 3251.742 pounds of water. The number of BTUs to raise it 188 degrees is then 611,327.496 BTUs.
You would need to remove approximately 1200 BTUs of heat to convert a gallon of water to ice. There are 8.34 lb in a gallon of water, which converting to lb-moles is 0.463. The latent heat of crystallization for water is -2583.4 BTU/lb-mole. Multiplying the two together and you get -1197 BTUs, which means you need to remove that amount of heat to convert the gallon of water to ice.
Heating a gallon of water by one degree Celsius requires around 8,337 BTUs (British Thermal Units) of energy. Since 1 cubic foot of natural gas produces about 1,031 BTUs, you would need roughly 8 cubic feet of natural gas to heat a gallon of water by one degree Celsius.
A gallon of kerosene typically contains about 135,000 BTUs of energy. At a burn rate of 30,000 BTUs per hour, a gallon of kerosene would last approximately 4.5 hours (135,000 BTUs ÷ 30,000 BTUs/hour = 4.5 hours). However, actual burn time can vary based on factors such as efficiency and burner design.
One gallon of kerosene will produce 134,000 BTUs of energy when burned.
That depends on what the starting temperature of the water is,and what temperature you want it to reach.If you expect to get a number, you must first give the necessary numbers.
Depends on the BTUs of the heater.
Type your answer here... there are around 91,600 BTUs in a gallon of propane. The standard BBQ sized bottle of propane contains 11 pounds of propane. Propane weighs about 4.2 pounds per gallon, so that 11 pounds of propane is about 2.5 gallons in its liquid state. That means there is 91,600 BTUs/Gal times 2.5 gallons so a BBQ sized tank of propane contains about 2.3 million BTUs. If your BBQ has a 50,000 BTU burner, on high heat, it will last a bit over 4 and half hours of run time.
1 gallon for #1 Kerosene produces 135,000 BTUs. #1 Kerosene is closely related to #1 Diesel and JP8 (Jet Fuel) - they differ chiefly in additives. Likewise, #2 Kerosene, Diesel #2, and Furnace Oil are similar to one another. #2 oils have higher sulfur content, which leads to more eye and lung irritation from the emissions. However, they are also comprised of longer hydrocarbon chains, and therefore weigh more per gallon and also have somewhat higher energy content.