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0.25*10-2*sin2*0.78=

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What is sine squared?

Answer 1 Put simply, sine squared is sinX x sinX. However, sine is a function, so the real question must be 'what is sinx squared' or 'what is sin squared x': 'Sin(x) squared' would be sin(x^2), i.e. the 'x' is squared before performing the function sin. 'Sin squared x' would be sin^2(x) i.e. sin squared times sin squared: sin(x) x sin(x). This can also be written as (sinx)^2 but means exactly the same. Answer 2 Sine squared is sin^2(x). If the power was placed like this sin(x)^2, then the X is what is being squared. If it's sin^2(x) it's telling you they want sin(x) times sin(x).


What is sin squared x minus cos squared x?

Sin squared, cos squared...you removed the x in the equation.


What is 10000 squared?

1000 squared is 100 .........daaa use a calculator


What is 9 squared take away 7 squared?

32 you should get a calculator


Is 2 sin squared x the same as 2 sin x?

No.


What is sin 7?

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How do you put sin on a calculator?

You need a scientific calculator, or one with function keys.


How do you prove that the sin over one minus the cosine minus one plus the cosine over the sine equals zero?

Multiply both sides by sin(1-cos) and you lose the denominators and get (sin squared) minus 1+cos times 1-cos. Then multiply out (i.e. expand) 1+cos times 1-cos, which will of course give the difference of two squares: 1 - (cos squared). (because the cross terms cancel out.) (This is diff of 2 squares because 1 is the square of 1.) And so you get (sin squared) - (1 - (cos squared)) = (sin squared) + (cos squared) - 1. Then from basic trig we know that (sin squared) + (cos squared) = 1, so this is 0.


What is Sin squared x - Cos squared x divided by 1 - Tan squared x equals cos squared x?

22


Does cos squared x over sin squared x equal cot squared x?

Yes. Except where sin x = 0, because then you would be dividing by zero so the quotient is undefined.


What is 1.53908 squared?

According to my Windows calculator... 2.3687672464


2x squared plus 2x?

use the calculator