x=y^2 may be written as y=+/-sqrt(x) The domain for sqrt(x) is [0, infinity). The range is also [0, infinity) However, y=+/-sqrt(x) is not a function, because one element in the domain has two values in the range set.
Yes, but x would be a function of y, not the other (usual) way round. The domain of the function would be y in (-infinity, +infinity) and the range x in [0, +infinity).
The range of -sin x depends on the domain of x. If the domain of x is unrestricted then the range of y is [-1, 1].
sqrt(x) Domain: {0,infinity) Range: {0,infinity) *note: the domain and range include the point zero.
domain is independent why? because its before range or also known as x/domain and y/range(x,y).
What is the domain and range of absolute lxl - 5
y6 x y2 y4 x y4 y2 x y2 x y4 y2 x y2 x y2 x y2
The answer depends on the domain for x. For example, if the domain is x = 7, then the range is 55. If the domain is all Real numbers, then the range is y >= 6.
The domain is the the set of inputs. (x) The range is the set of oututs. (y)
The range is the y value like the domain is the x value as in Domain and Range.
Find all possible "x" and "y" values for domain and range. Then put it in inequality form. For example the domain and range for the equation 2x-3/x-5 would be: Domain: All Reals; x>5 Range: All Reals
x is a letter often used as a variable. It can be in the range or the domain. However, in elementary algebra, the variable x is most often used for the domain and f(x) =y for the range.
You do not graph range and domain: you can determine the range and domain of a graph. The domain is the set of all the x-values and the range is is the set of all the y-values that are used in the graph.