A parabola with an equation, y2 = 4ax has its vertex at the origin and opens to the right. It's not just the '4' that is important, it's '4a' that matters. This type of parabola has a directrix at x = -a, and a focus at (a, 0). By writing the equation as it is, the position of the directrix and focus are readily identifiable. For example, y2 = 2.4x doesn't say a great deal. Re-writing the equation of the parabola as y2 = 4*(0.6)x tells us immediately that the directrix is at x = -0.6 and the focus is at (0.6, 0)
right
Yes, as x-y2=0
y2-x-6y+6=0 y2-6y+6=x (y-3)2-3=x so y = 3+sqrt(x+3) or y = 3-sqrt(x+3)
Type your answer here. Find the radius for a circle with the equation x2 plus y2 equals 9? ..
A parabola with an equation, y2 = 4ax has its vertex at the origin and opens to the right. It's not just the '4' that is important, it's '4a' that matters. This type of parabola has a directrix at x = -a, and a focus at (a, 0). By writing the equation as it is, the position of the directrix and focus are readily identifiable. For example, y2 = 2.4x doesn't say a great deal. Re-writing the equation of the parabola as y2 = 4*(0.6)x tells us immediately that the directrix is at x = -0.6 and the focus is at (0.6, 0)
the standard form of the equation of a parabola is x=y2+10y+22
There are two standard form of parabola: y2 = 4ax & x2 = 4ay, where a is a real number.
Y2 = Xtake square root each sideY = (+/-) sqrt(X)=============now it is a function as both these equation pass the vertical line test
8
right
left
Yes, as x-y2=0
y2-x-6y+6=0 y2-6y+6=x (y-3)2-3=x so y = 3+sqrt(x+3) or y = 3-sqrt(x+3)
Type your answer here. Find the radius for a circle with the equation x2 plus y2 equals 9? ..
when you have y=+/-x2 +whatever, the parabola opens up y=-(x2 +whatever), the parabola opens down x=+/-y2 +whatever, the parabola opens right x=-(y2 +whatever), the parabola opens left so, your answer is up
cos(pi) = -1 so the equation becomes x = -y2. That is equivalent to y = sqrt(-x) The domain of this function is x ≤ 0. The graph of the function is the same as that of a unit parabola in the first quadrant rotated anticlockwise by pi/2 radians.