Electrical breakers are sized by the conductor that is connected to it. The conductor is sized by the current that is drawn by the circuit. The formula for amperage is I = W/E. Amps + Watts/Volts. 325/120 = 2.7 amps. A #14 copper conductor is rated at 15 amps. This is the minimum size wiring that is used for house circuits loads. The breaker for this size wiring will be a 15 amp breaker.
50 watt equals less than 1/2 amp current flow at 120 volts so you can have 30 light on a 15amp breaker or 40 on a twenty amp breaker.
Take the plug in your hand, and insert the plug into the wall outlet.
The smallest size breaker is a 15 amp and with a #14 wire which has a capacity for 15 amps and a 120 volt source, this combination will give you the capacity up to 1800 watts. W = A x V, 120 x 15 = 1800.
The formula to use is I = W/E, assuming that the single breaker is delivering 120 volts, the amperage to the circuit is 16.6 amps. A continuous load on a 20 amp breaker has to be reduced to 80% according to the electrical code. 20 x .8 = 16. So to answer the question, yes, a 20 amp breaker will support a 2000 watt load at 120 volts.
Each baseboard heater will draw a little over 4 amps at 120 volts or 2 Amps at 240 volts. The total number of baseboards on a circuit will draw the sum of these amps. Keep the load under 80% of the amperage rating of the breaker.
To calculate the breaker size for a 1500-watt 120-volt heater, use the formula: Breaker size = Power (Watts) / Volts. In this case, 1500 watts / 120 volts = 12.5 amps. Therefore, you would need a 15-amp breaker for a 1500-watt 120-volt heater to allow for a safety margin.
For a 2500 watt water heater operating at 120 volts, you would need a 20 amp breaker. This ensures the breaker can handle the load without tripping.
Assuming this is standard house voltage of 120 VAC your 4500 Watt heater will draw about 37.5 amps. You would normally install a 50A breaker and would have to run 8 gauge wire.
A 1500 watt bathroom exhaust fan heater should be connected to a 15 amp breaker to ensure proper protection against overloads. This is calculated by dividing the wattage (1500 watts) by the voltage (typically 120 volts for residential circuits) to determine the amperage (12.5 amps in this case, which you would round up to the nearest standard breaker size).
At 120 Volts your heater is drawing about 12.5 Amps. If your house only had 120 V then it would draw 13.6 Amps. Problems could be 1.) Other devices on same circuit. 2.) Internal short in the heating element that reduced resistance and increased current. 3.) Faulty heater in that it really delivers more than 1500 watts because heating elements are less resistance than rating would require. 4.) Faulty breaker. These are in order of likelihood. You are close enough to the limit of the breaker that it could be any of these things. Typically you should not exceed 80% of the breaker rating and that is just where you are operating.
To find the amperage of a 750-watt heater operating at 120 volts, you can use the formula: Amps = Watts / Volts. Therefore, 750 watts divided by 120 volts equals 6.25 amps. So, a 750-watt heater uses approximately 6.25 amps.
To find the current in amps that a 750 watt, 120 volt heater draws, you can use the formula: Amps = Watts / Volts. So, 750 watts divided by 120 volts equals 6.25 amps. Therefore, the heater draws approximately 6.25 amps.
Yes, a 1500 watt heater operating on 120 volts has an amperage of A = W/V. Amps = Watts/Volts = 1500/120 = 12.5 amps. It is not a recommended practice to do so.
A 300 watt bulb requires a circuit breaker of at least 2.5 amps. This can be determined by dividing the power (300 watts) by the voltage (120 volts). However, considering normal breaker sizes, a 5 amp breaker would be sufficient for a 300 watt bulb.
50 watt equals less than 1/2 amp current flow at 120 volts so you can have 30 light on a 15amp breaker or 40 on a twenty amp breaker.
A 120 volt, 600 watt light draws approximately 5 amps. In the US, electrical codes specify that continuous load current should not be more than 80% of the breaker rating, so a 10A breaker would be the minimum size standard breaker. However, if this is a practical situation (as opposed to a basic arithmetic problem), it would be very unusual to put in a 10A circuit. Most residential lighting circuits are designed to carry 15A, even if that is not the immediate requirement. The occupant could decide to increase the load in the future.
Current (amps)=Watts/Volts =2000/120 =16.75 =16.75 amps