To determine the appropriate amp breaker for a 3700-watt element, you can use the formula: Amps = Watts / Volts. Assuming a standard voltage of 240 volts, the calculation would be 3700 watts / 240 volts = approximately 15.4 amps. It is advisable to use a 20-amp breaker for safety and to accommodate any inrush current, ensuring the breaker can handle the load without tripping.
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about 4800 watt but should not use it 100% so to be safe 4000 watt (80%)
a 220 volt, 3200 watt oven will draw under 15 amps, so yes a 2o amp breaker will work.
50 watt equals less than 1/2 amp current flow at 120 volts so you can have 30 light on a 15amp breaker or 40 on a twenty amp breaker.
A sauna heating element is a resistive load. The equation that you are looking for is Amps = Watts/Volts = 8000/220 = 36 amps. A #8 copper conductor with an insulation rating of 90 degrees C is rated at 55 amps. This will be fed with 40 amp two pole breaker.
Not unless you change the wiring for that circuit. The breaker protects the wiring and if you install a 40 amp breaker on a 15 amp wire circuit you will have a fire in your home.