The use of a breaker in a circuit is to protect the wire size used in the circuit from becoming overloaded. Using the wattage of the load does not help for breaker sizing because the breaker operates on amperage. Amperage can be found from wattage by using the following equation. I = W /E. Amps = Watts / Volts. As you can see the amperage can not be calculated because there is no voltage stated.
This formula will give you the amperage I = kw x 1000/1.73 x E x pf (pf = power factor). Take the amperage and multiply it by 125%. This will give you the breaker size that you need.
AWG #3 copper.
In standard construction this would require a 15 amp breaker and 14 gauge copper wire.
A 5 kW generator would turn it over but if the full 30 hp of mechanical power is needed, that would require about 30 kW of electric power from the generator.
3000 / 240 = Amps. You de-rate a breaker by 20 % for continuous load like an oven. You could get by with a 20 Amp breaker and 12 AWG wire. However, I would recommend 30 Amps and 10 AWG for an oven for the long run.
A breaker protects the wire size of the feeder that is connected to it. The amperage of the load must be found. Without a voltage stated the amperage from the wattage given can not be calculated. The equation for amperage when the kw is given is A = kW x 1000/1.73 x volts x pf. The pf constant to use is .9.
The formula you are looking for is I = W/E.
I=270000/380/1.732 I=410A USE: 500A CIRCUIT BREAKER
the given kw Divide by the your voltage
This formula will give you the amperage I = kw x 1000/1.73 x E x pf (pf = power factor). Take the amperage and multiply it by 125%. This will give you the breaker size that you need.
AWG #3 copper.
In standard construction this would require a 15 amp breaker and 14 gauge copper wire.
To determine the appropriate circuit breaker size for a 4.5 kW heater, first calculate the current using the formula: Current (I) = Power (P) / Voltage (V). Assuming a standard voltage of 240V, the current would be 18.75 amps (4,500W / 240V). It's advisable to choose a circuit breaker rated higher than the calculated current to account for potential surges and to ensure safety; a 20-amp circuit breaker would typically be suitable for this application. Always consult a qualified electrician for specific installations.
Calculate the ampereage at .8 pf and take a breaker of 150% of ampere nd set the over current protection at 125% of full load current.
To determine the appropriate circuit breaker size for a 9.4 kW three-phase machine, you can use the formula: Breaker Size (Amps) = Power (Watts) / (Voltage × √3). Assuming a standard voltage of 400V, the calculation would be approximately 13.5 Amps. It's advisable to select a breaker rated higher than this calculated value, typically rounding up to the nearest standard size, such as a 16A or 20A breaker, to account for inrush currents and ensure safety. Always consult local electrical codes and a qualified electrician for specific requirements.
Cant tell for sure. A good engine will have a small cc for its KW, while a crap one will require more cc. CC relates to the size of the engine, while kw refers to the power. Id say a 125 at a guess
7200