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This would be fairly common values (I assume the 11MV, or 11,000,000 volts is actually 11kV) for three phase power, so assuming this is true:

1000kW = 11kV * I * sqrt(3),

I = 52.5Amps of real power.

It is likely the actual measured value of I will be more than 52.5A, because almost no load is purely resistive in nature (thus you will have reactive power as well) which is not accounted for when strictly looking at watts).

A true measurement of expected current would be done using the KVA (the vector sum of kW and kVAR) value instead of the kW value (real power).

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15y ago

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