This would be fairly common values (I assume the 11MV, or 11,000,000 volts is actually 11kV) for three phase power, so assuming this is true:
1000kW = 11kV * I * sqrt(3),
I = 52.5Amps of real power.
It is likely the actual measured value of I will be more than 52.5A, because almost no load is purely resistive in nature (thus you will have reactive power as well) which is not accounted for when strictly looking at watts).
A true measurement of expected current would be done using the KVA (the vector sum of kW and kVAR) value instead of the kW value (real power).
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How many Amps is the fridge pulling? Multiply the Amps by the 120V circuit you're plugging into and you'll get your Watts.
It depends on how many Amps (current) are applied to the voltage. Watt = Volts x Amps. e.g. 12 volts @ 5 amps = 60 watts
Mega means million and a watt is a unit of power. A megawatt hour is the amount of power used if 1,000,000 watts are used for 1 hour, or 1 watt is used for 1,000,000 hours. If 100 light bulbs each using 1,000 watts of power are turned on for 10 hours, they will use 100 x 1,000 x 10 watt hours = 1,000,000 watt hours = 1 megawatt hour. Most electric companies charge for the number of kilowatt hours used. A megawatt hour is 1,000 kilowatt hours.
A watt is a measurement of Power (and a megawatt is a million watts) A volt a measurement of Electric Potential Difference The are related thus: W=VxA, or V=W/A So if you know the amperage, you can figure out the voltage: V = 3,400,000,000watts/?amps Your question is like asking how many feet are in an acceleration
8,000 since 8000*1000(kilo)=8,000,000 (mega)