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If you meant center at (2,4) and radius 3 then it would be: (X-2)^2 + (Y-4)^2 = r^2 (X-2)^2 + (Y-4)^2 = 3^2 Then the answer is: (X-2)^2 + (Y-4)^2 = 9

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How do you write an equation for a circle with a center?

Equation of any circle, with any radius, and its center at any point: [ x - (x-coordinate of the center) ]2 + [ y - (y-coordinate of the center) ]2 = (radius of the circle)2


How do you write an equation in standard form of a circle with a center and radius?

The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2


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The general equation for the circle - or one of them - is: (x - a)^2 + (y - b)^2 = r^2 Where: a and b are the coordinates of the center r is the radius


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How do you find the radius and the coordinates of the center for each circle?

The answer depends on what information is available and in what form.The simplest solution is to write the equation of the circle in the following form:(x - a)^2 + (y - b)^2 = r^2Hiving done that, the coordinates of the centre are (a, b), and the circle's radius is r.


How do you write the formula to a circle in the form x?

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What is the center of the circle given by the equation ((x plus 5)2 (y-8)21?

The equation you provided appears to be incorrectly formatted. However, if you meant to write the standard form of a circle's equation, which is ((x - h)^2 + (y - k)^2 = r^2), then the center of the circle is given by the point ((h, k)). For the specific equation you intended, please clarify the format, and I can help identify the center accordingly.


How do you write an equation for a circle graph with center at (-42) and radius 5?

The general form of the equation passing through the point (a,b) is (x-a)^2 + (y-b)^2=r^2 where ^2 means to the power of 2 or squared. So insert the point (-4,2) and radius, 5 is: (x+4)^2 + (y-2)^2=25


How do you write an equation for a circle graph with center at -4 2 and radius 5?

The general form of the equation passing through the point (a,b) is (x-a)^2 + (y-b)^2=r^2 where ^2 means to the power of 2 or squared. So insert the point (-4,2) and radius, 5 is: (x+4)^2 + (y-2)^2=25

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