Equation of any circle, with any radius, and its center at any point: [ x - (x-coordinate of the center) ]2 + [ y - (y-coordinate of the center) ]2 = (radius of the circle)2
The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2
The general equation for the circle - or one of them - is: (x - a)^2 + (y - b)^2 = r^2 Where: a and b are the coordinates of the center r is the radius
One it to write it would be:sqrt((x+2)^2+(y-3)^2)=6
The inner circle is x2 + y2 = 4. The radius of the inner circle is the square root of 4, which is 2. To find the radius of the outer circle, multiply 2 times 4. The radius of the outer circle is 8. Square 8 (82 or 8 x 8) to find the number to put into the equation of the outer circle. This is 64. The equation for the outer circle is x2 + y2 = 64.
The answer depends on what information is available and in what form.The simplest solution is to write the equation of the circle in the following form:(x - a)^2 + (y - b)^2 = r^2Hiving done that, the coordinates of the centre are (a, b), and the circle's radius is r.
(x - A)2 + (y - B)2 = C2 (A,B) is the center of the circle. 'C' is the circle's radius.
Rewrite the above program so that the program accepts any value for the radius then recalculate the area of the circle.
35/60 x 360 = 210
The general form of the equation passing through the point (a,b) is (x-a)^2 + (y-b)^2=r^2 where ^2 means to the power of 2 or squared. So insert the point (-4,2) and radius, 5 is: (x+4)^2 + (y-2)^2=25
The general form of the equation passing through the point (a,b) is (x-a)^2 + (y-b)^2=r^2 where ^2 means to the power of 2 or squared. So insert the point (-4,2) and radius, 5 is: (x+4)^2 + (y-2)^2=25
Formula for a circle with centre (xo, yo) and radius r is: (x - xo)2 + (y - yo)2 = r2 Circle centre (0, 0) and radius 14: (x - 0)2 + (y - 0)2 = 142 x2 + y2 = 196