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Write the equation in slope intercept form of the line that has a slope of 2 and Y intercept of 2?
The slope-intercept form of an equation is: y = mx + b Just copy down this equation, then replace "m" with the slope, and "b" with the y-intercept.
Write the equation of a line in slope intercept form that has a slope of 2 and contains the point of 4 2?
It is: y = 2x-6
Write the equation of a line in slope intercept form that has a slope of 4 and passes through the point 2 7?
Slope-intercept form: y = mx + b, where m is the slope and b is the y-intercept.By using the slope, m = 4 and the point (x1, y1) = (2, 1), write the point-slope equation of a line:(y - y1) = m(x - x1)(y - 1) = 4(x -2)y - 1 = 4x - 8 add 1 to both sidesy = 4x - 7Thus, the slope-intercept form is y = 4x - 7.
Write the equation in slope intercept form of the line that has a slope of 2 and contains the point 1 1?
y = 2x - 1
How do you find the standard form of a linear equation knowing only the y intercept and the slope IE A line has a slope of 5 over 3 and a y intercept of 1 over 2 State the equation in standard form?
Since we know the slope, m = 5/3, and the y-intercept 1/2, we arw able to write the equation of the line in the slope-intercept form, y = mx + b, so we have y = (5/3)x + 1/2.The standard form of the equation of the line is Ax + By = C.y = (5/3)x + 1/2y - y - 1/2 = (5/3)x - y + 1/2 - 1/2-1/2 = (5/3)x - y or(5/3)x - y = -1/2Thus, the standard form, Ax + By = C, of the equation of the line is (5/3)x - y = -1/2.
