The slope-intercept form of an equation is: y = mx + b Just copy down this equation, then replace "m" with the slope, and "b" with the y-intercept.
It is: y = 2x-6
Slope-intercept form: y = mx + b, where m is the slope and b is the y-intercept.By using the slope, m = 4 and the point (x1, y1) = (2, 1), write the point-slope equation of a line:(y - y1) = m(x - x1)(y - 1) = 4(x -2)y - 1 = 4x - 8 add 1 to both sidesy = 4x - 7Thus, the slope-intercept form is y = 4x - 7.
y = 2x - 1
Since we know the slope, m = 5/3, and the y-intercept 1/2, we arw able to write the equation of the line in the slope-intercept form, y = mx + b, so we have y = (5/3)x + 1/2.The standard form of the equation of the line is Ax + By = C.y = (5/3)x + 1/2y - y - 1/2 = (5/3)x - y + 1/2 - 1/2-1/2 = (5/3)x - y or(5/3)x - y = -1/2Thus, the standard form, Ax + By = C, of the equation of the line is (5/3)x - y = -1/2.
2.197*103
y=a(bx) is the standard form
Y=abx + c is the general form.
y=logx becomes 10^y=x
An exponential function is of the form y = a^x, where a is a constant. The inverse of this is x = a^y --> y = ln(x)/ln(a), where ln() means the natural log.
It is: y = -2x+2
x + y = -2 y = -x - 2 f(x)= - x -2
4
Logb (x)=y is called the logarithmic form where logb means log with base b So to put this in exponential form we let b be the base and y the exponent by=x Here is an example log2 8=3 since 23 =8. In this case the term on the left is the logarithmic form while the one of the right is the exponential form.
That all depends on the problem given!A general form of the exponential growth/decay is:y = ab^x.If we have an exponential growth, b = 1 + rOtherwise, b = 1 - r.In the second version, the exponential growth is y = Ae^(kt) while the exponential decay is y = Ae^(-kt)
If you mean: y+4 = -3(x-2) then y = -3x+2
y=2(to the x)-1