Slope-intercept form: y = mx + b, where m is the slope and b is the y-intercept.
By using the slope, m = 4 and the point (x1, y1) = (2, 1), write the point-slope equation of a line:
(y - y1) = m(x - x1)
(y - 1) = 4(x -2)
y - 1 = 4x - 8 add 1 to both sides
y = 4x - 7
Thus, the slope-intercept form is y = 4x - 7.
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
The slope-intercept form of an equation is: y = mx + b Just copy down this equation, then replace "m" with the slope, and "b" with the y-intercept.
-7
The slope of x and the y intercept as for example in the straight line equation of y = 2x+3 the slope is 2 and the y intercept is 3
8
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
Slope-intercept form
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4
y=-3x-2
You can write it either in standard form (ax + by = c) or in slope-intercept form (y = mx + b)
As for example the perpendicular equation to line y = 2x+6 could be y = -1/2x+6 because the negative reciprocal of 2x is -1/2x
It is: y-7 = -3(x--3) => y = -3x-2
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
The slope intercept form through 23 and 15 would be 5. This is considered as a math equation.
-12
sda
y= slope + y-intercept