Pretty sure it's a 1/3 of the volume of the cylinder so it would be 100 cm^3
volume=pi*radius squared*height/3, where radius is the radius of the cylinder (and will be the radius of the base of the cone),and height is the lenth of the cylinder.
The given description fits that of a cone shape.
The description given fits that of a cylinder
A quarter of a circleImproved Answer:-It fits the the description of a cylinder
It fits the description of a cube
volume=pi*radius squared*height/3, where radius is the radius of the cylinder (and will be the radius of the base of the cone),and height is the lenth of the cylinder.
Volume of a cone is 1/3 of the volume of the cylinder into which it just fits. So 1/3 x pi x 36 x 22 = about 829.7
The shape described has two flat faces, one curved face, and two edges. It could be a cylinder or a cone with a circular base.
"large density" ===> (relatively large mass) fits into (relatively small volume)
You have a cube with a volume of 64 cubic meters. The volume of a cube is V=s³, where s is the length of a side of the cube. 4×4×4=64, so the cube is 4 meters on a side.You now have a cylinder that fits inside that cube. That means that it is 4 meters high and has a diameter on the base of 4 meters, giving it a radius of 2 meters. The volume of a cylinder is V=πr²h, where r is the radius and h is the height. That works out to π×2²×4 = 16π, or about 50.265 cubic meters.
You measure height, width and depth (in feet), then multiply. I believe the "cubic feet" refers to what fits inside, i.e. the usable volume, so you'll have to measure on the inside.
A cone fits the description.
The given description fits that of a cone shape.
The given description fits that of a cone shape.
The description given fits that of a cone.
The description given fits that of a cone shape
The description given fits that of a cone.