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The perimeter of a rectangle can be expressed as [2 * ( L+ W )]. The area of a rectangle can be expressed as [L * W]. Thus, the equation can be written as:
2 * ( L + W ) = L * W
The answer originally posted on this page suggested the only solution is when the shape of the rectangle (four-sided object, opposite sides are equal length) is a square (four-sided object, all sides are equal length) with sides equal to 4.
Actually, a 6 x 3 (or 3 x 6) rectangle satisfies the equation, as it has an area and perimeter both equal to 18.
Keep in mind this is considering the rectangle sides must have integer values (positive number that is not a fraction), which is actually in accordance with the way the problem was posed going back to its original roots.
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Do figures with the same perimeter have the same area?
not necessarily. take the example of a 3x3 square and a 4x2 rectangle. Both have a perimeter of 12. but the square has an area of 9 and the rectangle has an area of 8.
Can two parallelograms have the same perimeter but different areas?
yes, for example: a 4 by 5 rectangle has an area of 20 and a perimeter of 18 a 2 by 7 rectangle has an area of 14 and a perimeter of 18 they both have a perimeter of 18
What is the perimeter of a rectangle with an area of 24cm?
The perimeter of the rectangle is the sum of its 4 sides.
The length of a rectangle is twice its width If the perimeter of the rectangle is 54y find its area?
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
A rectangle has a perimeter of 10 ft Write the area A of the rectangle as a function of the length of one side x of the rectangle?
This question has no unique answer. A (3 x 2) rectangle has a perimeter = 10, its area = 6 A (4 x 1) rectangle also has a perimeter = 10, but its area = 4 A (4.5 x 0.5) rectangle also has a perimeter = 10, but its area = 2.25. The greatest possible area for a rectangle with perimeter=10 occurs if the rectangle is a square, with all sides = 2.5. Then the area = 6.25. You can keep the same perimeter = 10 and make the area anything you want between zero and 6.25, by picking different lengths and widths, just as long as (length+width)=5.
