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Given ef is the midsegment of isosceles trapezoid abcd bc equals 17x ef equals 22.5x plus 9 and ad equals 30x plus 12 find ad?
bc = ad = 75 Tan adb = 160/75 = 2.1333 (4dp), so angle adb = 64.885°.
First of all we work out the length of a sides ab, bc, CD, & ad. We know that ab = bc = CD = ad also ae = ac/2 If a to e = 2 then ac = 4 so ab2 + bc2 = ac2 2ab2 = 16 ab2 = 8 ab = 2.8284271247461900976033774484194 so the perimeter = ab * 4 = 11.31
bc equals st multiplied by the scale factor.
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Given ef is the midsegment of isosceles trapezoid abcd bc equals 17x ef equals 22.5x plus 9 and ad equals 30x plus 12 find ad?
Anything you like (as long as it is > -16 so that BC > 0). In a parallelogram, adjacent sides do not impose any restrictions on one another.
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bc = ad = 75 Tan adb = 160/75 = 2.1333 (4dp), so angle adb = 64.885°.
If you mean quadrilateral ABCD then by using the cosine rule diagonal AC equals 5.71 cm and diagonal BD equals 6.08 cm both rounded to two decimal places.
Assuming ABCD marks the four corners, the perimeter = sum of the four sides = (AB + BC + CD + DA) where AB == the side from A to B etc.
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First of all we work out the length of a sides ab, bc, CD, & ad. We know that ab = bc = CD = ad also ae = ac/2 If a to e = 2 then ac = 4 so ab2 + bc2 = ac2 2ab2 = 16 ab2 = 8 ab = 2.8284271247461900976033774484194 so the perimeter = ab * 4 = 11.31