52.4 cm
You're given side AB with a length of 6 centimeters and side BC with a length of 5 centimeters. The measure of angle A is 30°. How many triangles can you construct using these measurements?
To find the length of segment AB, we can use the segment addition postulate, which states that the total length of a segment is equal to the sum of the lengths of its parts. Therefore, AB + BC = AC. Given that AC = 78 mm and BC = 29 mm, we can substitute these values into the equation to find AB: AB + 29 = 78. Solving for AB, we get AB = 78 - 29 = 49 mm.
Using trigonometry and Pythagoras' theorem the diagonal length of AC works out as 10.05 cm rounded to two decimal places.
EC = 9 in. CD = in. Find ED
\8
-+-
Unfortunately, the browser used for posting questions is hopelessly inadequate for mathematics: it strips away most symbols. In the third sentence, all that we can see is "If 2BE AD BC 10 and area of ABCD P ... ". From that it is not at all clear what the missing symbols (operators) might be. It makes little sense for me to try and guess - I may as well make up my own questions and answer them!
Given ef is the midsegment of isosceles trapezoid abcd bc equals 17x ef equals 22.5x plus 9 and ad equals 30x plus 12 find ad?
25
The length is sqrt(61) units.
AD,BC, and AE
In order to find length BC the length of AC or length of the hypotenuse must be given
25 units
bc equals st multiplied by the scale factor.
First of all we work out the length of a sides ab, bc, CD, & ad. We know that ab = bc = CD = ad also ae = ac/2 If a to e = 2 then ac = 4 so ab2 + bc2 = ac2 2ab2 = 16 ab2 = 8 ab = 2.8284271247461900976033774484194 so the perimeter = ab * 4 = 11.31
26.17