52.4 cm
You're given side AB with a length of 6 centimeters and side BC with a length of 5 centimeters. The measure of angle A is 30°. How many triangles can you construct using these measurements?
Using trigonometry and Pythagoras' theorem the diagonal length of AC works out as 10.05 cm rounded to two decimal places.
EC = 9 in. CD = in. Find ED
If the quadrilateral is a square then all of its sides are the same length. ac is not one of the sides but is a diagonal which forms the hypotenuse of a right angle triangle with sides ab and bc. According to Pythagoras the sum of the square of the hypotenuse is equal to the sum of the squares of the other two sides. As side ab measures 10 then 10 squared = 100. Side bc has the same measurements. The square of side ac must equal 200 (100 + 100) so the length of side ac must equal the square root of 200 (100 + 100) which is 14.14 (to 2 decimal places).
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Given ef is the midsegment of isosceles trapezoid abcd bc equals 17x ef equals 22.5x plus 9 and ad equals 30x plus 12 find ad?
25
The length is sqrt(61) units.
AD,BC, and AE
In order to find length BC the length of AC or length of the hypotenuse must be given
25 units
bc equals st multiplied by the scale factor.
First of all we work out the length of a sides ab, bc, CD, & ad. We know that ab = bc = CD = ad also ae = ac/2 If a to e = 2 then ac = 4 so ab2 + bc2 = ac2 2ab2 = 16 ab2 = 8 ab = 2.8284271247461900976033774484194 so the perimeter = ab * 4 = 11.31
26.17
Find the length of each sideside ab and bc differ in length by 10cm and the side ac and bc differ in length 3cmfind the lenght of each sideperimeter of a triangle abc is 103cm?